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3 years ago

A distribution of values is normal with a mean of 1986.1 and a standard deviation of 27.2.

Mathematics

1 answer:

m_a_m_a [10]3 years ago

4 0

Answer:

I used the function normCdf(lower bound, upper bound, mean, standard deviation) on the graphing calculator to solve this.

Lower bound = 1914.8
Upper bound = 999999
Mean = 1986.1
Standard deviation = 27.2

Input in these values and it will result in:

normCdf(1914.8,9999999,1986.1,27.2) = 0.995621

So the probability that the value is greater than 1914.8 is about 99.5621%

I'm not sure if this is correct 0_o

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Carey and Patrick both borrowed money from Melinda. Carey owes Melinda $25.00. Patrick owes Melinda 3/4 the amount that Carey ow

iragen [17]

Answer:

$18.75

Step-by-step explanation:

multiply 25 * 3/4 ( 0.75) and you get 18.75

4 0

3 years ago

Find the area of a square with side length 4/5 yard.

BigorU [14]

Answer:

side length = 0.8 yards

area = side length^2= 0.8^2 = 0.64 or 64/100

Step-by-step explanation:

hope that helped

6 0

3 years ago

Read 2 more answers

Three vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.

topjm [15]

Given:

The three vertices of a parallelogram are (-3,8), (4,5), (2,-5).

To find:

The fourth vertex of the parallelogram.

Solution:

Let the vertices of the parallelogram are A(-3,8), B(4,5), C(2,-5) and D(a,b).

We know that, diagonals of a parallelogram bisect each other. It means midpoints of both diagonals are same.

Midpoint formula:

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

Two diagonals of ABCD are AC and BD.

Midpoint of AC = Midpoint of BD

$\left(\dfrac{-3+2}{2},\dfrac{8-5}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)$

$\left(\dfrac{-1}{2},\dfrac{3}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)$

On comparing both sides, we get

$\dfrac{4+a}{2}=\dfrac{-1}{2}$

$4+a=-1$

$a=-1-4$

$a=-5$

And,

$\dfrac{5+b}{2}=\dfrac{3}{2}$

$5+b=3$

$b=3-5$

$b=-2$

Therefore, the coordinates of fourth vertex are (-5,-2).

3 0

3 years ago

My grade is a 77%, if i get a 0% on a paper worth 30% of my grade, what will my grade be now??

blsea [12.9K]

$Grade=Paper+Other$
$Grade=(Grade_{paper}\times Value_{paper})+(Grade_{other}\times Value_{other})$
$Grade=(0 \times 30\%)+(77\% \times (1-30\%))$
$Grade=(0 \times 30\%)+(77\% \times 70\%)$
$Grade=0+53.9\%$
$Grade=53.9\%$

6 0

3 years ago

Solve by factoring x^2-8x-9 = 0

3241004551 [841]

Answer:

the answer is ( x-9) (x+1) = 0

Step-by-step explanation: