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3 years ago

A distribution of values is normal with a mean of 1986.1 and a standard deviation of 27.2.

Mathematics

1 answer:

m_a_m_a [10]3 years ago

4 0

Answer:

I used the function normCdf(lower bound, upper bound, mean, standard deviation) on the graphing calculator to solve this.

Lower bound = 1914.8
Upper bound = 999999
Mean = 1986.1
Standard deviation = 27.2

Input in these values and it will result in:

normCdf(1914.8,9999999,1986.1,27.2) = 0.995621

So the probability that the value is greater than 1914.8 is about 99.5621%

<u><em>I'm not sure if this is correct </em></u><em>0_o</em>

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2 years ago

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<h3>What is the missing end of the line segment?</h3>

In this problem we know the locations of one end of the line segment and the midpoint and the location of the missing end has to be found by means of the vectorial form of the midpoint formula:

0.5 · A(x, y) + 0.5 · C(x, y) = B(x, y)

0.5 · A(x, y) = B(x, y) - 0.5 · C(x, y)

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To learn more on midpoints: brainly.com/question/28224145

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