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kipiarov [429]
2 years ago
5

A distribution of values is normal with a mean of 1986.1 and a standard deviation of 27.2.

Mathematics
1 answer:
m_a_m_a [10]2 years ago
4 0

Answer:

I used the function normCdf(lower bound, upper bound, mean, standard deviation) on the graphing calculator to solve this.

  • Lower bound = 1914.8
  • Upper bound = 999999
  • Mean = 1986.1
  • Standard deviation = 27.2

Input in these values and it will result in:

normCdf(1914.8,9999999,1986.1,27.2) = 0.995621

So the probability that the value is greater than 1914.8 is about 99.5621%

<u><em>I'm not sure if this is correct </em></u><em>0_o</em>

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