I think frequency it sounds like the correct answer but I am not completely sure if I am correct
Given a = 10 cm/s²
u = 0 cm/s
v = 50 cm/s
we know that
v²=u²+2aS
2500=2×10×S
2500÷20 = S
S= 125 cm
The ramp is 125 cm
no BECQUSE POSUM BROOB SHSHSJ
In this problem,
Applied force(F) = 10 N
The object’s mass (m) is 5 kg.
Having said that,
An object’s force is equal to the product of its mass and the acceleration it experiences as a result of the applied force.
i.e., Mass + Acceleration = Force (a)
F= m×a
Therefore,
A= F÷m
A= (10÷5) m/sec²
A= 2 m/sec²
Consequently, the object’s acceleration,
A=2 m/sec²
Concept of force and acceleration:
This states that the rate of velocity change of an object is directly proportional to the applied force and moves in the direction of the applied force.
It can be expressed mathematically as force (N) = mass (kg) x acceleration (m/s2). Therefore, an object with constant mass will accelerate in direct proportion to the applied force.
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