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kramer
3 years ago
15

In a free body diagram the weight is

Physics
1 answer:
torisob [31]3 years ago
7 0

Answer:

Explanation:

a. WEIGHT: As we have seen, weight is the gravitational force exerted on an object by the Earth (or any other celestial body). If an object is near the Earth's surface and has mass, then the object has a weight. The magnitude of its weight is w = mg and its direction is toward the center of the Earth.

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Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weigh
BabaBlast [244]

Answer:

<h2>E. 650N</h2>

Explanation:

step one:

given

length of stretcher= 2m

weight of stretcher=100N

Wayne weighs =800N

distance of Wayne weighs from chris's end= 75cm= 0.75m

The force that Chris is exerting to support the stretcher, with Wayne on it, can be computed by taking moments of the weight of the stretcher and Wayne weighs  about Chris's end, the end result is the reaction at Chris's end

Taking moment about Chris's end

The moment of Wayne weight 75cm from Chris+ Half the weight of stretcher 1m from Chris

0.75*800+50*1=0

600+50=0

650N

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3 years ago
What does kidney disease affect the immune system
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It can hurt and harm the body on many different and levels 
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4 years ago
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The short-circuiting logical operators ____. Group of answer choices enable doing as little as is needed to produce the final re
ohaa [14]

Answer:

D. cause the program to stop execution when the expression is evaluated

Explanation:

D. cause the program to stop execution when the expression is evaluated

7 0
4 years ago
3. A snowmobile has a mass of 2.25 x 102 kg. A constant force is exerted on it for 50.0 s. The snowmobile’s initial velocity is
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Answer:

a. m(v-u)

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3 0
3 years ago
A marble rolls off a table with a speed of 2.30 m/s. If the table is 1.12 m high, how far from the
Vlada [557]

Answer:

1.10 m

Explanation:

First, find the time it takes to land.

Given, in the y direction:

Δy = 1.12 m

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a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

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Next, find the distance traveled in that time.

Given, in the x direction:

v₀ = 2.30 m/s

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Find: Δx

Δx = v₀ t + ½ at²

Δx = (2.30 m/s) (0.478 s) + ½ (0 m/s²) (0.478 s)²

Δx = 1.10 m

6 0
4 years ago
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