All categories

2 years ago

What is the value of acceleration of a body if it is in uniform velocity

Physics

1 answer:

Eddi Din [679]2 years ago

5 0

Answer:

Zero

Explanation:

The acceleration of body moving with uniform velocity is zero, because there is no change in velocity.

You might be interested in

How Many Negative (-) Electrons are there

makvit [3.9K]

Answer:

All electrons are negative(-) charged

5 0

3 years ago

PLZ HELP I WILL GIVE BRAINLIEST

Vaselesa [24]

Answer:

12.7m/s

Explanation:

Given parameters:

Mass of diver = 77kg

Height of jump = 8.18m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we apply the motion equation below:

v² = u² + 2gH

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

H is the height

Now insert the parameters and solve;

v² = 0² + 2 x 9.8 x 8.18

v = 12.7m/s

8 0

2 years ago

A police car is stopped at a red light facing west. When the light turned green, a sports car speeds past it heading west at wit

frutty [35]

Answer:

14 seconds

Explanation:

Distance covered by sports car is measured with 21*t where t is time.

Distance covered by police is measured with at^2/2(t-time, a-acceleration) as it doesnt have starting velocity. If the distances are equal(police catches sport car)

then we have 21t=3/2*t^2 Solving this equation we get t=14 & t=0;

excluding the starting point we have 14 seconds

3 0

3 years ago

Read 2 more answers

A 6.75 nC charge is located 1.99 m from a 4.46 nC point charge.

sladkih [1.3K]

Explanation:

Given that,

Charge 1, $q_1=6.75\ nC=6.75 \times 10^{-9}\ C$

Charge 2, $q_2=4.46\ nC=4.46\times 10^{-9}\ C$

The distance between charges, r = 1.99 m

To find,

The electrostatic force and its nature

Solution,

(a) The electric force between two charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

$F=\dfrac{9\times 10^9\times 6.75\times 10^{-9}\times 4.46\times 10^{-9}}{(1.99)^2}$

$F=6.84\times 10^{-8}\ N$

(b) As the magnitude of both charges is positive, then the force between charges will be repulsive.

Therefore, this is the required solution.

5 0

3 years ago

A golf ball (m = 59.2 g) is struck a blow that makes an angle of 50.5 ◦ with the horizontal. The drive lands 130 m away on a fla

fomenos

Answer:

The force is calculated as 338.66 N

Explanation:

We know that force is given by

$\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{m(v_{f}-v_{o})}{\Delta t}$

We know that range of a projectile is given by

$R=\frac{v_{o}^{2}sin(2\theta )}{g}$

it is given that R=130 m applying values in the above equation we get

$R=\frac{v_{o}^{2}sin(2\theta )}{g}\\\\v_{0}=\sqrt{\frac{Rg}{sin(2\theta )}}\\\\\therefore v_{o}=\sqrt{\frac{130\times 9.81}{sin(2\times 50.5_{o}} )}\\\\v_{o}=36.04m/s$

Thus the force is obtained as

$\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{59.2\times 10^{}-3(36.04-0)}{6.3\times 10^{-3}}$

Thus force equals $F=338.66N$

4 0

3 years ago

Read 2 more answers

What is the value of acceleration of a body if it is in uniform velocity​

What is the value of acceleration of a body if it is in uniform velocity