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Vinvika [58]
3 years ago
7

Determine the right answer to fill in the blank spaces

Physics
1 answer:
ratelena [41]3 years ago
5 0

Answer:

Explanation:

A pure substance is something that is entirely made up of particles that are identical to each other.

Any substance that is not pure, must be a mixture.

We are surrounded by mixtures. The air is a mixture of gases . The oceans are a mixture of (mainly) water and salt. The solid earth is mostly rock, which is a mixture of different minerals.

Natural resources are substances we need and use, which occur naturally. Some come from living things, (example) cotton other are non-living (example)  sand.

The opposite of a natural resource is a made resource.

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Monochromatic light from a distant source is incident on a slit 0.705 mm wide. On a screen 2.13 m away, the distance from the ce
vampirchik [111]

Answer:

492.183 nm

Explanation:

x = Distance from the central maximum to the first minimum = 1.35 mm

l = Distance of screen = 2.13 m

d = Distance of gap = 0.705 mm

m = Order = 1

We have the relation

tan\theta=\dfrac{x}{l}\\\Rightarrow \theta=tan^{-1}\dfrac{1.35\times 10^{-3}}{2.13}\\\Rightarrow \theta=0.04^{\circ}

dsin\theta=m\lambda\\\Rightarrow \lambda=\dfrac{dsin\theta}{m}\\\Rightarrow \lambda=\dfrac{0.705\times 10^{-3}\times sin0.04}{1}\\\Rightarrow \lambda=4.92183\times 10^{-7}=492.183\ nm

The wavelength of the light is 492.185 nm

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3 years ago
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Troposphere is the highest atmospheric layer.
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false the answer is Exosphere :D

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3 years ago
Which sentence states Newton’s third law?
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<span>If two objects collide, each object exerts a force equal to and in the opposite direction of the other.</span>
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3 years ago
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A rider on a bike with the combined mass of 100 kg attains a terminal speed of 15 m/s on a 12% slope. Assuming that the only for
vlabodo [156]

Answer:

0·95

Explanation:

Given the combined mass of the rider and the bike = 100 kg

Percent slope = 12%

∴ Slope = 0·12

Terminal speed = 15 m/s

Frontal area = 0·9 m²

Let the slope angle be β

tanβ = 0·12

As it attains the terminal speed, the forces acting on the combined rider and the bike must be balanced and therefore the rider must be moving download as the directions of one of the component of weight and drag force will be in opposite directions

The other component of weight will get balance by the normal reaction and you can see the figure which is in the file attached

From the diagram m × g × sinβ = drag force

Drag force = 0·5 × d × C_{D} × v² × A

where d is the density of the fluid through which it flows

C_{D} is the drag coefficient

v is the speed of the object relative to the fluid

A is the cross sectional area

As tanβ = 0·12

∴ sinβ = 0·119

Let the fluid in this case be air and density of air d = 1·21 kg/m³

m × g × sinβ = 0·5 × d × C_{D} × v² × A

100 × 9·8 ×0·119 = 0·5 × 1·21 × C_{D} × 15² × 0·9

∴ C_{D} ≈ 0·95

∴ Drag coefficient is approximately 0·95

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