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prohojiy [21]
3 years ago
9

How many moles are in 5g of Al?A.0.185B.18.5C.5.4D.135

Chemistry
2 answers:
ycow [4]3 years ago
7 0
The answer is •D)135• it added up to 134.91 but if you round it it’s 135☻︎
Lapatulllka [165]3 years ago
3 0
I got 134.91 but if you round it you’ll get 135
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A student placed equal volumes of honey and of water in two, identical, open dishes, and left them at room temperature for 8 hou
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Answer: Honey has a much lower vapor pressure than pure water has. So, pure water evaporates at a much higher rate.

Explanation:

8 0
3 years ago
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If the absorbance of a KMnO4 solution of unknown concentration is 0.633, calculate the concentration of KMnO4 in the solution.
solong [7]

The molar Concentration of KMnO₄ is 0.000219 M

Concentration is the abundance of a constituent divided by means of the overall extent of an aggregate. numerous styles of mathematical description may be outstanding: mass awareness, molar awareness, variety concentration, and quantity awareness.

y is absorbance

x is the molar concentration of KMnO_4

y = 4.84E + 03x - 2.26E - 01

0.833 = 4.84 * 10⁺⁰³ x - 2.26 * 10⁻¹

1.059 = 4.84 * 10⁺⁰³ x

X = 0.000219 M

Hence, The molar Concentration of KMnO₄ is 0.000219 M

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3 0
1 year ago
When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0
3 years ago
Blast furnaces extract pure iron from the iron(III) oxide in iron ore in a two step sequence. In the first step, carbon and oxyg
zavuch27 [327]

Answer:

6 C(s) +  3 O₂(g) + 2 Fe₂O₃(s) →  4 Fe(s) + 6 CO₂(g)

Explanation:

Iron can be formed in two steps.

Step 1: 2 C(s) + O₂(g) → 2 CO(g)

Step 2: Fe₂O₃(s) + 3 CO(g) → 2 Fe(s) + 3 CO₂(g)

In order to get the net chemical equation, we will multiply the first step by 3, the second step by 2, and then add them.

6 C(s) +  3 O₂(g) → 6 CO(g)

+

2 Fe₂O₃(s) + 6 CO(g) → 4 Fe(s) + 6 CO₂(g)

--------------------------------------------------------------------------------------------------

6 C(s) +  3 O₂(g) + 2 Fe₂O₃(s) + 6 CO(g) → 6 CO(g) + 4 Fe(s) + 6 CO₂(g)

6 C(s) +  3 O₂(g) + 2 Fe₂O₃(s) →  4 Fe(s) + 6 CO₂(g)

6 0
3 years ago
Hydrogenation reactions, in which H2 and an "unsaturated" organic compound combine, are used in the food, fuel, and polymer indu
ddd [48]

<u>Answer:</u> The amount of heat released is 56 MJ.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of C_2H_6 = 12 kg = 12000 g    (Conversion factor: 1 kg = 1000 g)

Molar mass of C_2H_6 = 30 g/mol

Putting values in above equation, we get:

\text{Moles of }C_2H_6=\frac{12000g}{30g/mol}=400mol

The chemical reaction for hydrogenation of ethene follows the equation:

C_2H_4+H_2\rightarrow C_2H_6

By Stoichiometry of the reaction:

When 1 mole of ethane releases 140 kJ of heat.

So, 400 moles of ethane will release = \frac{140}{1}\times 400=56000kJ of heat.

Converting this into Mega joules, using the conversion factor:

1 MJ = 1000 kJ

So, \Rightarrow 56000kJ\times (\frac{1MJ}{1000kJ})=56MJ

Hence, the amount of heat released is 56 MJ.

8 0
3 years ago
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