First we will calculate free energy change:
ΔG₀ = ΔH₀ - (T * ΔS₀)
= - 793 kJ - (298 * - 0.319 kJ/K) = - 698 kJ
We know the relation between free energy change and cell potential is:
ΔG₀ = - n F E⁰ where
F = Faraday's constant = 96485 C/mol
n = 2 (given by equation that the electrons involved is 2)
ΔG₀ = - 2 x 96485 x E⁰
- 698 kJ = - 2 x 96485 x E⁰
E⁰ = (698 x 1000) / (2 x 96485) = 3.62 volts
4Al+6Fe(NO3)2= 6Fe+4Al(NO3)3
Explanation:
From your information above, assume 1 month is 28 days
1 days=24hours ; 28 days=672 hours (just multiply 1 days with 28)
1 hour=60minutes ; 672 hours=40,320 minutes
.. 1 month=40,320 minutes
