Answer:
Zn(s) + Cu²⁺(aq) ⇒ Zn²⁺(aq) + Cu(s)
Explanation:
Let's consider the molecular single displacement equation between Zn and Cu(NO₃)₂
Zn(s) + Cu(NO₃)₂(aq) ⇒ Zn(NO₃)₂(aq) + Cu(s)
The complete ionic equation includes all the ions and insoluble species.
Zn(s) + Cu²⁺(aq) + 2 NO₃⁻(aq) ⇒ Zn²⁺(aq) + 2 NO₃⁻(aq) + Cu(s)
The net ionic equation includes only the ions that participate in the reaction and insoluble species.
Zn(s) + Cu²⁺(aq) ⇒ Zn²⁺(aq) + Cu(s)
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I think its 896,,, got the other side which is 34 then multiplied that and 28
I would measure by its height and width
Answer:
10 L
Explanation:
We'll begin by calculating the number of mole in 9 g and 1 g of He. This can be obtained as follow:
Mass of He = 9 g
Molar mass of he= 4 g/mol
Mole of He =?
Mole = mass /Molar mass
Mole of He = 9/4
Mole of He = 2.25 moles
Mass of He = 1 g
Molar mass of he= 4 g/mol
Mole of He =?
Mole = mass /Molar mass
Mole of He = 1/4
Mole of He = 0.25 moles
Finally, we shall determine the new volume of the balloon as follow:
Initial mole (n₁) = 0.25 mole
Initial volume (V₁) = 1 L
Final mole (n₂) = 0.25 + 2.25 = 2.5 moles
Final volume (V₂) =?
V₁/n₁ = V₂/n₂
1 / 0.25 = V₂ / 2.5
4 = V₂ / 2.5
Cross multiply
V₂ = 4 × 2.5
V₂ = 10 L
Therefore, the new volume of the balloon is 10 L