Answer:
The magnitude of the average force needed to bring the chihuahua to a stop is 23.96 N
Explanation:
Newton's second law states that the acceleration of an object is inversely proportional to the mass of the object. The greater the mass of an object, the less its acceleration will be if a given net force is applied to it. In other words, mass is a property of objects that opposes acceleration when a force is applied.
In this way, Newton's second law says that the acceleration of a body is proportional to the resultant of forces on the acting and inversely proportional to its mass. This is expressed by the mathematical relationship:
F = m * a
where:
F = Force [N]
m = Mass [kg]
a = Acceleration []
You know that 3.63 kg chihuahua charges at a speed of 3.3m/s and you need to bring the chihuahua to a stop in 0.50s.
A motion is uniformly varied rectilinear when the trajectory of the mobile is a straight line and its speed varies by the same amount in each unit of time, so that the acceleration is constant. In this case the uniformly varied rectilinear motion is fulfilled. Being:
velocity (final) = velocity (initial) + acceleration * time
vf = vi + a * t
the acceleration is:
In this case:
Replacing:
Solving:
a= -6.6
Then the magnitude of the average force can be calculated as:
F=m*a
F=3.63 kg* (-6.6 )
Solving:
<u><em>F= - 23.96 N</em></u>
<u><em>The magnitude of the average force needed to bring the chihuahua to a stop is 23.96 N</em></u>
<u><em></em></u>
Answer:
a)
b)
Explanation:
a) The displacement of the first object is 22.5 m, so we can use the next equation:
positive acceleration.
b) Using the same equation we can find the second value of the acceleration:
positive acceleration.
I hope it helps you!
Answer:
Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.
Explanation:
Considering the complete question attached in figure below.
Time period for balance wheel is:
m = mass of balance wheel
R = radius of balance wheel.
Angular frequency is related to Time period as:
As dimensions of new balance wheel are one-third of their original values
The correct answer is
C. Light can pass through Object B faster than it can pass through Object A.
In fact, the index of refraction of a material is defined as:
where c is the speed of light in vacuum and v is the speed of light in the material. Rearranging the equation, we can write the speed of light in the material as:
So we that, the smaller the refractive index n, the greater the speed of light in the material, v. In this problem, object B has lower refractive index than object A, so light travels faster in object B.