Answer:
16 m
Explanation:
For an object in uniformly accelerated motion (=with constant acceleration), the distance covered by the body can be found by using the following suvat equation:
where
s is the distance covered
u is the initial velocity
t is the time
a is the acceleration
For the body in this problem,
u = 0 (it starts from rest)
is the acceleration
Substituting t = 4 s, we find the distance covered:
The new natural frequency would be ω/2.
we know that,
= ω. -> equation 1
now, when capacitance is quadrupled,
. -> equation 2
substituting value of equation 1 in equation 2 , we get,
Hence, the new natural frequency of the circuit is ω/2.
what do you mean by frequency ?
The resonant frequency for a particular circuit is the frequency at which this equality stands true. Where L is the inductance in henries and C is the capacitance in farads, this is the LC circuit's resonant frequency.
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With the use of below formula, at 879 °C, velocity will be double the velocity at 15 °C.
<h3>What is the relationship between Velocity and sound ?</h3>The velocity of sound waves in air is proportional to the square root of Thermodynamic temperature. That is, V = K
Given that the temperature at which the velocity of sound in air is twice its velocity at 15°C, Let us make use of the formula;
(v2/v1) = √(T2 / T1)
Where
Recall that absolute temperature = °C + 273.
If v2 = 2 × v1 and temperature in degree Celsius = 15°C, then,
Temperature in Kelvin K = 15 + 273 = 288
Substitute all the parameters into the formula
(2 × v1)/v1 = √(T2/288)
2 = √ (T2 /288)
Square both sides
4 = (T2/288)
T2 = 4 × 288
T2 = 1152K
Temperature in degrees Celsius = 1152 - 273 = 879 °C.
Therefore, at 879 °C, velocity will be double the velocity at 15 °C.
Learn more about sound waves here: brainly.com/question/13105733
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