Answer:
F = 1.24*10^4 N
Explanation:
Given
Depth of the ship, h = 25 m
Density of water, ρ = 1.03*10^3 kg/m³
Diameter of the hatch, d = 0.25 m
Pressure of air, P(air) = 1 atm
Pressure of water =
P(w) = ρgh
P(w) = 1.03*10^3 * 9.8 * 25
P(w) = 2.52*10^5 N/m²
P(net) = P(w) + P(air) - P(air)
P(net) = P(w)
P(net) = 2.52*10^5 N/m²
Remember,
Pressure = Force / Area, so
Force = Area * Pressure
Area = πr² = πd²/4
Area = 3.142 * 0.25²/4
Area = 3.142 * 0.015625
Area = 0.0491 m²
Force = 0.0491 * 2.52*10^5
F = 12373 N
F = 1.24*10^4 N
An object's momentum is the product of its mass and its velocity:
p = mv
p is its momentum, m is its mass, and v is its velocity.
Given values:
p = -80kg×m/s
m = 8kg
Plug in these values and solve for v:
-80 = 8v
v = -10m/s
Choice D
Answer:
(a)
M = 1.898 x 10^27 kg
(b)
v = 13.74 km/s
(c) E = 0.28 N/kg
Explanation:
Time period, T = 3.55 days = 3.55 x 24 x 3600 second = 306720 s
Radius, r = 6.71 x 10^8 m
G = 6.67 x 10^-11 Nm^2/kg^2
(a) 


M = 1.898 x 10^27 kg
(b) Let v be the orbital velocity


v = 13739.5 m/s
v = 13.74 km/s
(b) The gravitational field E is given by


E = 0.28 N/kg
Answer:
mph
Explanation:
= Speed of bird in still air
= Speed of wind = 44 mph
Consider the motion of the bird with the wind
= distance traveled with the wind = 9292 mi
= time taken to travel the distance with wind
Time taken to travel the distance with wind is given as

eq-1
Consider the motion of the bird with the wind
= distance traveled against the wind = 6060 mi
= time taken to travel the distance against wind
Time taken to travel the distance against wind is given as

eq-2
As per the question,
Time taken with the wind = Time taken against the wind





mph
(aq)
This means it’s aqueous (dissolved in water)