Do you not understand how to solve for the answer?
Answer:
0.42 m/s²
Explanation:
r = radius of the flywheel = 0.300 m
w₀ = initial angular speed = 0 rad/s
w = final angular speed = ?
θ = angular displacement = 60 deg = 1.05 rad
α = angular acceleration = 0.6 rad/s²
Using the equation
w² = w₀² + 2 α θ
w² = 0² + 2 (0.6) (1.05)
w = 1.12 rad/s
Tangential acceleration is given as
= r α = (0.300) (0.6) = 0.18 m/s²
Radial acceleration is given as
= r w² = (0.300) (1.12)² = 0.38 m/s²
Magnitude of resultant acceleration is given as


= 0.42 m/s²
The wavelength decreases to roughly half.
(The frequency roughly doubles.)
(a) 
The change in energy of the transferred charge is given by:

where
q is the charge transferred
is the potential difference between the ground and the clouds
Here we have


So the change in energy is

(b) 7921 m/s
If the energy released is used to accelerate the car from rest, than its final kinetic energy would be

where
m = 950 kg is the mass of the car
v is the final speed of the car
Here the energy given to the car is

Therefore by re-arranging the equation, we find the final speed of the car:

Explanation:
Yes, it takes more energy to vaporize 1 kg of saturated liquid water at than it would at .