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3 years ago

8

A particle of mass 2kg resting on a smooth table attached to a fixed point on the table by a rope 1.0m making 300revolution per

minute. Find the tension in the rope.

1 answer:

zepelin [54]3 years ago

7 0

Answer is: 1973.17N aprox.
step by step in the pic below

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If one oscillation has 5. 8 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?

quester [9]

The ratio of their amplitudes will be 2.41.

To find the answer, we have to know more about the simple harmonic motion.

<h3>How to find the ratio of their amplitudes?</h3>

It is given that,

$E_1=5.8E_2\\m_1=m_2 \\\omega_1=\omega_2$

We have the relation between these quantities and amplitudes as,

$A=\sqrt\frac{2E}{k} \\k=m\omega^2$

Here, for both the oscillation, k will be same.

Thus, the ratio of amplitude will be,

$\frac{A_1}{A_2} =\sqrt{\frac{E_1}{E_2} } =\sqrt{\frac{5.8E_2}{E_2} } =2.41$

Thus, we can conclude that, the ratio of their amplitudes will be 2.41.

Learn more about simple harmonic motion here:

brainly.com/question/22422926

#SPJ4

7 0

2 years ago

A buoy is a floating device that can have many purposes, but often as a locator for ships. Collin constructs a hollow metal buoy

Yuri [45]

Answer:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water

B )angular frequency ( w ) = $\sqrt{\frac{3g}{h} }$

c ) h = 1.34 m ( 4 $\pi ^{2}$ / 3g )

Explanation:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water this is because the substances with lesser density floats when placed in a substance with a higher density

B ) when the Buoy is at rest ( t = 0 ) and is then pushed down calculate angular frequency ( w ) of small oscillations in terms of the given variables

volume of cone = hA /3.

h = height of cone, A = Base Area.

therefore the total volume of the Buoy above water level ( at rest )

= ( $\pi r^{2} * \frac{h}{3}$ ) * 2 = $\frac{\pi r^{2} h }{6}$

The part of the buoy immersed in water = x

then the net upward force will be

fb ( force of Buoy ) = fg ( force of gravity )

note force = Mass * Acceleration

force of buoy = $\frac{\alpha }{2} *$ $\frac{\pi r^{2} }{h}$ * a = ( force of gravity ) $\alpha * T\frac{r^{2} }{4} * x * g$

therefore a = $\frac{3g}{h} * x$

angular frequency ( w ) = $\sqrt{\frac{3g}{h} }$

C ) height of the each cone

$\frac{2\pi }{w} = 1$ therefore w = 2 $\pi$

back to the angular frequency : $\frac{3g}{h} = 4\pi ^{2}$

therefore h = 1.34 m ( 4 $\pi ^{2}$ / 3g )

4 0

3 years ago

What sound signal alerts others that a boat is backing up?

inn [45]

"Three short blasts" sound signal alerts others when a boat is backing up based on the boating safety rule. The short blast is a sound which has one second period, thus three short blasts mean three of this kind of sound. The sound signal is used for alerting anything surrounding the boat to avoid a collision.

5 0

3 years ago

What two elements are named after Dimitri Mendeleev?

bezimeni [28]

I'm pretty sure there is only one element named after Mendeleev: <span>Mendelevium.</span>

8 0

3 years ago

Read 2 more answers

if a sample that is 4860 years old has 50 radium atoms remaining, how many atoms were in the original sample?

snow_lady [41]

243000, take the 4,860 and times it by 50

4 0

3 years ago