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2 years ago

Como converter 13 graus em radianos?

Mathematics

1 answer:

victus00 [196]2 years ago

8 0

Answer:

13 grados es igual a 0.226893 radianes

Step-by-step explanation:

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The coordinates of the image of line segment RT are R’(-2, -4) and T’(4, 4). The image was produced by a dilation with a scale f

lukranit [14]

Answer:

R(-4,-8) and T(-8,8)

Step-by-step explanation:

Dilation multiplies or divides. Since it is .5 dilation, the pre-image has greater points.
This multiplying each end point by 2 gives us our pre-image values.

4 0

3 years ago

Evaluate the double integral.

Fynjy0 [20]

Answer:

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

Step-by-step explanation:

The equation of the line through the point $(x_o,y_o)$ & $(x_1,y_1)$ can be represented by:

$y-y_o = m(x - x_o)$

Making m the subject;

$m = \dfrac{y_1 - y_0}{x_1-x_0}$

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

$m= \dfrac{2-1}{1-0}$

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

$m = \dfrac{1-2}{4-1}$

$m = \dfrac{-1}{3}$

∴

$y-2 = -\dfrac{1}{3}(x-1)$

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

$\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg) dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ([y^2(-4y+8)] \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( -4y^3+8y^2 \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{-45+56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{11}{3}\bigg]$

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

4 0

2 years ago

What is the length of a diagonal of a rectangular picture whose sides are 12 inches by 17 inches? Round to the nearest tenth of

Nostrana [21]

Answer: d≈20.81in

Hope this helpsss!!!

6 0

3 years ago

The students in Ms. Lorenzo’s class collected the following numbers of bottle caps:

gladu [14]

I am not sure how to show you how to do a dot plot on this website, but to see how to do a dot plot

b) Put everything in order and find the middle
10, 10, 10, 20, 30, 30, 30, 30, 40, 50, 50, 50, 60, 60, 70, 70, 2040
^^
So 40 is in the middle, making it the median

c) Add all of the values together and divide by the total number of values.
10 + 10 + 10 + 20 + 30 + 30 + 30 + 30 + 40 + 50 + 50 + 50 + 60 + 60 + 70 + 70 + 2040 = 2660
2660 / 17 = 156.5

5 0

2 years ago

Which table represents a linear function that has a slope of 5 and a y-intercept of 20?

AVprozaik [17]

Answer:

Step-by-step explanation:

Note that if it has a y- intercept of 20, this means that when x = 0 , y = 20

Find the table which shows that :)

3 0

2 years ago