Answer: 1 < x < 2
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
1/2r +1/2= -2/7r -29/7 Subtracting 1/2 from both sides
1/2r +1/2 - 1/2= -2/7r -29/7- 1/2
1/2r = -2/7r - 29(2)-7/14
1/2r = -2/7r -65/14
Answer: 29 = 5/6
Step-by-step explanation:
first you would convert 1 2/3 into a improper faction. So you would multiply 1 and 3 then add 2 so 5/3 then multiply that by 1/2. You would multiply the numerators and denominators, so 5 times 1 and 3 times 2 which gives you 5/6.
Answer:
Option a) circle 5 meters and 22 meters
Step-by-step explanation:
We are given the following information in the question:
A pair of diameter and the circumference is given. We have to find a correct approximations for the diameter and circumference.
a) circle 5 meters and 22 meters
![\text{Diameter} = 5\text{ meters}\\\text{Circumference} = \pi d = 3.14\times 5 = 15.7\text{ meters}](https://tex.z-dn.net/?f=%5Ctext%7BDiameter%7D%20%3D%205%5Ctext%7B%20meters%7D%5C%5C%5Ctext%7BCircumference%7D%20%3D%20%5Cpi%20d%20%3D%203.14%5Ctimes%205%20%3D%2015.7%5Ctext%7B%20meters%7D)
b) 19 inches and 50 inches
![\text{Diameter} = 19\text{ inches}\\\text{Circumference} = \pi d = 3.14\times 19 = 59.66\text{ inches}](https://tex.z-dn.net/?f=%5Ctext%7BDiameter%7D%20%3D%2019%5Ctext%7B%20inches%7D%5C%5C%5Ctext%7BCircumference%7D%20%3D%20%5Cpi%20d%20%3D%203.14%5Ctimes%2019%20%3D%2059.66%5Ctext%7B%20inches%7D)
c) 33 centimeters and 80 centimeters
![\text{Diameter} = 33\text{ centimeters}\\\text{Circumference} = \pi d = 3.14\times 33 =103.62\text{ centimeters}](https://tex.z-dn.net/?f=%5Ctext%7BDiameter%7D%20%3D%2033%5Ctext%7B%20centimeters%7D%5C%5C%5Ctext%7BCircumference%7D%20%3D%20%5Cpi%20d%20%3D%203.14%5Ctimes%2033%20%3D103.62%5Ctext%7B%20centimeters%7D)
Thus, no pair gives a reasonable approximation. Only the circle with diameter 5 and circumference 22 meters have closest approximation.
Answer:
(-16.494 ; -3.506)
Step-by-step explanation:
student Prob A Prob B difference, d (A-B)
1 20 35____ - 15
2 30 40 ___ - 10
3 15 20 ___ - 5
4 40 50 __ - 10
Difference, d = -15, -10, -5, -10
Xd = Σd/ n = - 40 / 4 = - 10
Standard deviation of d ; Sd = 4.082
The confidence interval for the difference is given as :
Xd ± Tcritical*(Sd/√n)
Tcritical at 95%; df = n - 1 ; 4 - 1 = 3
Tcritical(0.05, 3)). = 3.182
C.I = -10 ± 3.182(4.082/√4)
C.I = -10 ± 6.494462
C. I = (-16.494 ; -3.506)