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drek231 [11]
3 years ago
7

Complete the following table based on known properties of ionic and covalent compounds.

Chemistry
1 answer:
TiliK225 [7]3 years ago
6 0

Answer:

structure of KF - ionic

Explanation:

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a certain gas occupies 5 dm³ at 24 °C and 15 cm Hg. Calculate the pressure of the gas if the volume is halved and the temperatur
Fantom [35]

Explanation:

<em>(</em><em>P1V1</em><em>)</em><em>/</em><em>T1</em><em>=</em><em>(</em><em>P2V2</em><em>)</em><em>/</em><em>T2</em>

<em>(</em><em>1</em><em>5</em><em>X</em><em>5</em><em>)</em><em>/</em><em>2</em><em>9</em><em>7</em><em>=</em><em>(</em><em>p2x2</em><em>.</em><em>5</em><em>)</em><em>/</em><em>4</em><em>7</em><em>3</em>

<em>p2</em><em>=</em><em>47.78cmHg</em>

7 0
3 years ago
How did rutherford's experimental evidence lead to the development of a new atomic number
borishaifa [10]
Rutherford's experiment was the gold foil experiment.

The gold foil experiment was him shooting alpha particles (you could think of this as a Helium atom without its electrons) into a gold foil. The whole experiment was surrounded with something called Zinc Sulfide which sparked when the alpha particles hit it.

Most of the alpha particles went through, approximately 1 in 8000 alpha particles deflected at a large angle (almost right back to where it was shot).

This constant ratio caused him to conclude that:-the atom was mostly empty space (since most alpha particles went through)-there was something very positive in the atom (the proton)-the proton was very dense (since it made something going light speed deflect back at a large angle)-The proton was also very small (since only 1 in 8000 hit it)

Prior to the discovery of the proton, John Dalton's periodic table was used. Having "elements" such as soda and potash. Now that we have discovered the proton and found out that each atom's number of protons is unique, we used that to classify each element's identity.
8 0
4 years ago
what mass of copper is produce when Zinc is added to a solution containing 31.9g copper (ii) tetraoxosulphate (vi)​
Sergio [31]

12.7 grams of copper will be produced.

<h3><u>Explanation</u>:</h3>

Copper is placed below zinc in the metal activity series. This means zinc can replace copper from its salt. Here zinc is added to the salt solution of copper sulphate. The reaction involved is

CuSO4 +Zn =ZnSO4 +Cu.

Zinc sulphate is soluble in the solution and rose red copper will be precipitated from the solution.

From the chemical equation we can see that 1 mole of zinc replaces 1 mole of copper. As no mass of zinc added is mentioned we will assume that excess of zinc is added.

Atomic mass of copper = 63.5

Atomic mass of sulphur = 32.

Atomic mass of oxygen = 16.

So molecular mass of copper sulphate = 63.5 + 32 + 4\times16 = 159.5.

So, mass of 1 mole of copper sulphate is 159.5 grams.

So, in 31.9 grams of copper sulphate, number of moles of copper sulphate present =\frac {159.5}{31.9} = 0.2

In 1 mole of copper sulphate, 1 mole of copper is present.

So in 0.2 moles of copper sulphate, 0.2 moles of copper is present.

So mass of 0.2 moles of copper = 0.2\times63.5 = 12.7 grams

8 0
4 years ago
Scoring Scheme: 3-3-2-1 Part I. How many mL of 6 M NaOH stock solution should be used to prepare the 500 mL of 0.2 M NaOH? Pleas
Orlov [11]

Answer : The volume of 6M NaOH stock solution is, 16.7 mL

Explanation :

To calculate the volume of NaOH stock solution, we use the equation given by neutralization reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of NaOH stock solution.

M_2\text{ and }V_2 are the molarity and volume of NaOH.

We are given:

M_1=6M\\V_1=?\\M_2=0.2M\\V_2=500mL

Putting values in above equation, we get:

6M\times V_1=0.2M\times 500mL\\\\V_1=16.7mL

Thus, the volume of 6M NaOH stock solution is, 16.7 mL

4 0
4 years ago
What is the definition of intrusive
Paha777 [63]
<span>causing disruption or annoyance through being unwelcome or uninvited.</span>
6 0
4 years ago
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