All categories

2 years ago

Complete the following table based on known properties of ionic and covalent compounds.

Chemistry

1 answer:

TiliK225 [7]2 years ago

6 0

Answer:

structure of KF - ionic

Explanation:

You might be interested in

Which process requires water to gain heat energy from the environment

elixir [45]

Answer:

Evaporation

Explanation:

Evaporation is the certain process that requires water to gain heat energy from the environment.

4 0

3 years ago

How many liters are there in 28g of B?

Juliette [100K]

Hi
The volume is 58.1
The moler mass is 10.8
Molar mass details
10.81B (1*10.81)

Hope this helps

5 0

2 years ago

Antimony has two naturally occuring isotopes, 121 Sb and 123 Sb . 121 Sb has an atomic mass of 120.9038 u , and 123 Sb has an at

valina [46]

Answer:

Percentage abundance of 121 Sb is = 57.2 %

Percentage abundance of 123 Sb is = 42.8 %

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 121 Sb :

% = x %

Mass = 120.9038 u

For second isotope, 123 Sb:

% = 100 - x

Mass = 122.9042 u

Given, Average Mass = 121.7601 u

Thus,

$121.7601=\frac{x}{100}\times 120.9038+\frac{100-x}{100}\times 122.9042$

$120.9038x+122.9042\left(100-x\right)=12176.01$

Solving for x, we get that:

x = 57.2 %

Thus, percentage abundance of 121 Sb is = 57.2 %

percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %

6 0

3 years ago

Will you be my Magnesium, Silver, Nitrogen but "9.8m/s²" is silent? Please help me here

zmey [24]

I don’t really understand but the symbols of these elements on the periodic table are

MgAgN

and 9.8 m/s^2 is the acceleration of gravity, commonly abbreviated as ‘g’

If you take out the ‘g’s from the periodic table equation(bc the question says 9.8m/s^2 is silent) it spells MAN

So the question could be “Will you be my man?”

4 0

3 years ago

The factor that affects how easily an electron can be removed from an atom is the.

zalisa [80]

Atomic radius aka distance from the nucleus to the outermost energy level. The greater this distance, the less electrostatic attraction between these oppositely charged particles.

4 0

3 years ago