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2 years ago

9

Making models involves creating representations of complex objects or processes to help people study and understand things that

cannot be observed directly. A. true B. false

1 answer:

swat322 years ago

6 0

Somewhat false
observations can be made of a model of the statue of liberty, say, or in real line

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Consider the following reaction where Kc = 154 at 298 K.2NO(g) + Br2(g) 2NOBr(g)A reaction mixture was found to contain 4.64×10-

IgorLugansk [536]

Answer:

The reaction is not at equilibrium and reaction must run in forward direction.

Explanation:

At the given interval, concentration of NO = $\frac{4.64\times 10^{-2}}{1}M=4.64\times 10^{-2}M$

Concentration of $Br_{2}$ = $\frac{4.56\times 10^{-2}}{1}M=4.56\times 10^{-2}M$

Concentration of NOBr = $\frac{0.102}{1}M=0.102M$

Reaction quotient, $Q_{c}$ , for this reaction = $\frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]}$

species inside third bracket represents concentrations at the given interval.

So, $Q_{c}=\frac{(0.102)^{2}}{(4.64\times 10^{-2})^{2}\times (4.56\times 10^{-2})}=106$

So, the reaction is not at equilibrium.

As $Q_{c}< K_{c}$ therefore reaction must run in forward direction to increase $Q_{c}$ and make it equal to $K_{c}$ .

4 0

2 years ago

Somebody help with A B and C please will give brain thanks

Norma-Jean [14]

Answer:

we cant see a b or c

Explanation:

7 0

2 years ago

Which fact below is describing a base?

QveST [7]

7<span> to 49 10 to 100. 30 Secs. 3. What is the </span>pH<span> value of pure </span>water<span>? 0 3 </span>7<span> 10 ... How do acids </span>taste<span>? </span>bitter sour<span> sweet salty. 30 Secs. </span>7<span>. How do </span>bases taste<span>? </span>bitter<span> ... 8. Which kind of solution would react with a metal? acidic basic </span>neutral water<span> ... cocoa </span>has<span> a </span>bitter taste<span>. It is most likely which of the following? acid </span><span>base neutral</span>

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3 years ago

29. A gas has a volume of 1.75 L at -23°C and 150.0 kPa.

arsen [322]

The answer for the following mention bellow.

<u><em>Therefore the final temperature of the gas is 260 k</em></u>

Explanation:

Given:

Initial pressure ( $P_{1}$ ) = 150.0 kPa

Final pressure ( $P_{2}$ ) = 210.0 kPa

Initial volume ( $V_{1}$ ) = 1.75 L

Final volume ( $V_{2}$ ) = 1.30 L

Initial temperature ( $T_{1}$ ) = -23°C = 250 k

To find:

Final temperature ( $T_{2}$ )

We know;

According to the ideal gas equation;

P × V = n × R ×T

where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

We know;

$\frac{P*V}{T}$ = constant

$\frac{P_{1} }{P_{2} }$ × $\frac{V_{1} }{V_{2} }$ = $\frac{T_{1} }{T_{2} }$

Where;

( $P_{1}$ ) represents the initial pressure of the gas

( $P_{2}$ ) represents the final pressure of the gas

( $V_{1}$ ) represents the initial volume of the gas

( $V_{2}$ ) represents the final volume of the gas

( $T_{1}$ ) represents the initial temperature of the gas

( $T_{2}$ ) represents the final temperature of the gas

So;

$\frac{150 * 1.75}{210 * 1.30}$ = $\frac{260}{T_{2} }$

( $T_{2}$ ) =260 k

<u><em>Therefore the final temperature of the gas is 260 k</em></u>

<u><em></em></u>

3 0

2 years ago

Which group of elements shares characteristics with both metals and nonmetals?

sertanlavr [38]

The answer to your question is,

Metalloids. They are a mix of elements that are both metals and non-metals in one.

-Mabel <3

4 0

3 years ago

Read 2 more answers