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Slav-nsk [51]
3 years ago
6

Determine the number of grams found in a 1.20 X 10^30 sample of carbonate ions.

Chemistry
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

my FBI'd Narayan Rouniyar

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Magnesium burns in air with a dazzling brilliance to produce magnesium oxide: 2 Mg(s) + O2(g) → 2 MgO(s) How many moles of O2 ar
TEA [102]

Answer:

1.05 mols of O2 gas

Explanation:

For this type of problem, it's important to understand what the balanced Chemical equation tells us:

<h3><u>Balanced Chemical equations</u></h3>

Let's look at the balanced chemical equation:

2Mg(s)+O_2(g)-- > 2MgO(s)

This equation two sides of the reaction arrow.  On the left are the reactants (things you start with, and that react during the chemical reaction), and on the right side are products (things that are produced during the chemical reaction that you end with).

The numbers in front of each compound tell how many of molecules are involved for a full reaction without anything left over.  A "mol" is a large quantity (6.022*10^{23}), in this case, of molecules , since it's unlikely you're only taking a single molecule of each substance (it would be so tiny, you wouldn't even know you were doing the reaction).

So,for every 2 moles of Magnesium used, we'll also need 1 mole of Oxygen, and it will produce 2 moles of Magnesium Oxide.

In a way, during the reaction it's almost like 2 moles of Magnesium is equal to 1 mole of Oxygen and is equal to 2 moles of Magnesium Oxide:

2 mol Mg(s)=1mol O_2(g)=2molMgO(s)

From here, we can build some unit ratios, to convert between the known quantity of moles we have, and find the unknown quantity of moles that are requested.

<h3><u>Finding the right unit ratio</u></h3>

We know that we are looking at 2.10 mol of Magnesium, so we want a unit ratio with moles of Mg on the bottom.  <u>We want to find moles of O2</u>, <u>so we want a unit ratio of moles of O2 on top</u>.

The unit ratio we want is the middle part of the equation, divided by the left part of the equation.

2 mol Mg(s)=1mol O_2(g)\\\frac{2 mol Mg(s)}{2 mol Mg(s)}=\frac{1mol O_2(g)}{2 mol Mg(s)}\\1=\frac{1mol O_2(g)}{2 mol Mg(s)}

Since this quantity is 1, it is a unit ratio and can be multiplied to other things to change their units (for this problem).

<h3><u>Finding the answer</u></h3>

Starting with what we know, and multiplying by our unit ratio:

2.10 mol Mg(s)*\frac{1mol O_2(g)}{2 mol Mg(s)}=1.05mol O_2(g)

Notice that the units from the first quantity cancel with the units on the bottom of the fraction, leaving only the unit on top of the fraction ... the exact units we wanted!

So, 1.05mols of O2 would be consumed during the reaction if exactly 2.10moles of Magnesium are burned.

4 0
2 years ago
What does the velocity of a wave describe
sveta [45]
The Velocity of a Wave<span>. If the crest of a slinky </span>wave<span> moves a distance of 20 meters in 10 seconds, then the speed of the ocean </span>wave<span> is 2 m/s. ... For a given </span>velocity<span>, if you increase the frequency, the wavelength </span>will<span> be shortened.</span>
5 0
4 years ago
If 21.42g of KMnO4 is actually produced what is the percent yield
mrs_skeptik [129]

Answer:

Percentage yield  = 6.776%

Explanation:

Data Given:

Actual yield of KMnO₄ = 21.42g

Percentage Yield = ?

Formula Used to find Percent yield

                 Percentage yield = Actual yield/ theoretical yield x 100        (1)

For this Pupose First step is

We have to know the theoretical yield KMnO₄

Potasium permagnate form from MnO₄ and KOH in the presence of Oxygen by heating, in 1st step in second 2K₂MnO₄ react with HCl and give KMnO₄ .

The Reactions of formation of KMnO₄

1st Step                      

2MnO₄ + 4KOH + O₂  ------------> 2K₂MnO₄ + 2H₂O

2nd Step

2K₂MnO₄ + 4HCl ------------->2 KMnO₄ + H₂O + 4KCl

So form the above equation we come to know it produced 2 Mole of KMnO₄

Now we will calculate the mass of KMnO₄ by mass formulae

     mass of KMnO₄ = Number of mole of KMnO₄ x Molar Mass of KMnO₄

Molar Mass of KMnO₄ = 158.034g /mol

Put value in Mass Formula

 mass of KMnO₄ = 2 mol x  158.034g/mol

mass of KMnO₄ = 316.1 g

So the theoratical yield per standard reaction = 316.1 g

Now put all values in equation 1

           Percentage yield = Actual yield/ theoretical yield x 100  

           Percentage yield  = 21.42g / 316.1 g x 100

          Percentage yield =  0.0678 x 100

          Percentage yield  = 6.776%

4 0
3 years ago
What is the valence of Hydrogen, Oxygen, Nitrogen, Chlorine, Carbon and Silicon
-Dominant- [34]
They are all substances
3 0
3 years ago
Read 2 more answers
Which electron in sulfur is most shielded from nuclear charge?
natima [27]

Answer: 3p Orbitals

Explanation:

Electrons present in the 3p orbitals are farthest from the nucleus. Therefore, the electrons present in the 3p orbital will be shielded by the electrons present in the inner orbitals. Hence, 3p orbital in sulfur is most shielded from the nuclear charge".

5 0
3 years ago
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