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baherus [9]
3 years ago
13

In Rutherford’s gold foil experiment, most alpha particles passed through the gold foil without deflection and were detected on

the screen. What caused the particles to pass through without any deflection?
Chemistry
2 answers:
earnstyle [38]3 years ago
8 0

In Rutherford's gold foil experiment, some of those particles were deflected back towards him and off to the side. This told him that the protons and electrons were not evenly dispersed. However, the particles that did pass through did so because the protons are located in a concentrated area in the center of the atom, and the electrons are dispersed in the empty space around it. At least, that is what Rutherford determined

Komok [63]3 years ago
4 0

<u>Answer:</u> The empty space in the nucleus let the particles pass through without any deflection.

<u>Explanation:</u>

Rutherford gave an experiment which is known as gold foil experiment.

In this experiment, he took a gold foil and bombarded it with the alpha particles that carries positive charge of 2 units. He expected that the particles will pass straight through the foil, but to his surprise, some of them deflected their path and a few of them bounced back.

From this he gave a result that an atom consist of empty space and also has a small positive charge which is present at the center. Due to this positive charge, the alpha particles deflected their path and some of them bounced straight back from their path.

As, the atom consist of alot of empty space. Thus, the alpha particles passed straight through without any deflection.

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Which of the following equations is balanced?
stiv31 [10]

Answer:

A) 4P + 5O₂  → 2P₂O₅

Explanation:

A) 4P + 5O₂  → 2P₂O₅

This equation is balanced. There are four phosphorus and ten oxygen atoms are on both side of equation.

B) 5P + 4O₂    →    2P₄O₅

This equation is not balanced. There are five phosphorus and eight oxygen atoms on left, eight phosphorus ten oxygen on right side of equation.

C) 2P + O₂    →      P₂O₅

This equation is not balanced. There are two phosphorus, two oxygen atoms on left and two phosphorus five oxygen on right side of equation.

D) 4P + 2O₂    →   2P₄O₅

This equation is not balanced. There are four phosphorus, four oxygen atoms on left and eight phosphorus ten oxygen on right side of equation.

4 0
3 years ago
What is the oxidation state for the common action of lithium?
forsale [732]

Answer:

atomic number 3

boiling point 1,342 °C (2,448 °F)

specific gravity 0.534 at 20 °C (68 °F)

oxidation state +1

electron configuration 2-1 or 1s22s1

Explanation:

i think this Is right 99% sure

6 0
4 years ago
What is the pH of a solution that is 0.40 M NaBrO and 0.50 M HBrO (hypobromous acid) (Ka for HBrO = 2.3 x 10^-9)
Pie

Answer

pH=8.5414

Procedure

The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.

pH = pKa + log₁₀ ([A⁻] / [HA])

Where

pH = acidity of a buffer solution

pKa = negative logarithm of Ka

Ka =acid disassociation constant

[HA]= concentration of an acid

[A⁻]= concentration of conjugate base

First, calculate the pKa

pKa=-log₁₀(Ka)= 8.6383

Then use the equation to get the pH (in this case the acid is HBrO)

pH=8.6383+\log_{10}(\frac{0.40\text{ M}}{0.50\text{ M}})=8.5414

8 0
1 year ago
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Natali5045456 [20]
The Answer Is A 21% oxygen and 78%nitrogen
5 0
4 years ago
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hodyreva [135]

Answer:

The answer is:

B

Explanation:

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Methane's outer atoms are dipoles and are in the same direction. This makes the overall molecule non-polar. The compound itself has non-polar bonds and it is non-polar itself.

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