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KonstantinChe [14]

3 years ago

5

Prelest! Introduction to Engineering and Technology 1 Select the correct answer. What technological invention allowed for the pr

evalence of automation? OA. external combustion engines OB. electromagnets OC. computers OD. internal combustion engines. please help me

1 answer:

satela [25.4K]3 years ago

7 0

Answer:

I would think OD. Computers

Explanation:

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A "type 30" brake chamber has a diaphragm diameter of 8" which gives it

Montano1993 [528]

The piston makes four strokes in the crankshaft makes two revolutions between combustion firings. The diameter of the piston, and the inside diameter of the cylinder, is called a bore, so the area of the head of the piston is pi times the diameter squared divided by four.

5 0

3 years ago

In modern construction, studs are usually cut to exact length at the mill. They are designated by the letters

ehidna [41]

Answer:

P.E.T

Explanation:

Stud is a short form of stud wall which are typically vertical framing members in a wall of a building. Wall studs are available in standard lengths but since the height of ceiling vary, sometimes one has to cut the stud walls on site to fit. Therefore, there are pre-cut studs which are more efficient in implementation. These are usually referred as Precision-End Trimmed studs, (P.E.T). Therefore, stud walls which are cut to exact length at the mill for modern construction are designated by letters P.E.T

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4 years ago

KVL holds for the supermesh, so we can write a KVL equation to generate the second equation we need to solve for the two unknown

kaheart [24]

Answer:

The values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA while that of V_Δ is -25 V

Explanation:

As the complete question is not given the complete question is found online and is attached herewith.

By applying KCL at node 1

$i_x+50mA=i_y\\i_x-i_y=0.05A$

Also

$V_{\Delta}=1K*i_y$

Now applying KVL on loop 1 as indicated in the attached figure

$1K*i_y+5K(i_y-i_z)+3K*i_x=0\\3i_x+6 i_y-5i_z=0$

Similarly for loop 2

$2V_{\Delta}+5K(i_z-i_y)=0\\2*1K*i_y+5K(i_z-i_y)=0\\2K*i_y+5K(i_z-i_y)=0\\3i_y-5i_z=0$

So the system of equations become

$i_x-i_y+0i_z=0.05\\3i_x+6i_y-5i_z=0\\0i_x-3i_y+5i_z=0$

Solving these give the values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA. Also the value of voltage is given as

$V_{\Delta}=1K*i_y\\V_{\Delta}=1K*-25 mA\\V_{\Delta}=-25 V$

The values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA while that of V_Δ is -25 V

8 0

3 years ago

A tee requires three studs and three cripples.<br> O TRUE<br> O FALSE

NARA [144]

Answer:

will you please explain more?

3 0

3 years ago

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State two main consumers of electricity transmitted at low frequency Calculate the primary voltage of a transformer if the prima

bagirrra123 [75]

Answer:

1) a. Customers requiring AC electric power transmission for powering remote devices which may include a subsea transmission system where power is distributed to subsea devices

b. Customers that utilize commutator-type motors

2) The primary voltage is 150 volts

Explanation:

The parameters given are;

Number of primary winding, $N_p$ = 50 turns

Number of secondary winding, $N_s$ = 150 turns

Voltage in secondary winding, $V_s$ = 450 volts

Voltage in primary winding = $V_p$

The relation between $N_p$ , $N_s$ , $V_s$ and $V_p$ is as follows;

$\dfrac{V_p}{V_s} = \dfrac{N_p}{N_s}$

Which gives;

$V_p = \dfrac{N_p \times V_s}{N_s}$

From which we have;

$V_p = \dfrac{50\times 450}{150} = 150 \ volts$

The primary voltage = 150 volts.

7 0

4 years ago

Read 2 more answers