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Cloud [144]
3 years ago
9

Which is a better conductor, a flagpole or a flag? Why?

Physics
2 answers:
sergeinik [125]3 years ago
7 0

Answer:Got It!

Explanation: if it is about electricity then its flagpole.

Novosadov [1.4K]3 years ago
4 0

Answer:

flagpole

Explanation:

if it is about electricity then its flagpole

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You lay a mirror flat on the floor with one edge against a wall and aim a laser at the mirror. The ray reflects from the mirror
joja [24]

Answer:

the angle of incidence θ is 45.56 º

Explanation:

Given data

strikes the mirror before wall x = 30.7 cm

reflected ray strikes the wall y =  30.1 cm

to find out

the angle of incidence θ

solution

let us consider ray is strike at angle  θ so after strike on surface ray strike to wall at angle 90 - θ

we will apply here right angle triangle rule that is

tan( 90 - θ) = y /x

tan( 90 - θ)  = 30.1 / 30.7

90 - θ = tan^-1 (30.1/30.7)

90 - θ = 44.4345

θ = 45.56 º

the angle of incidence θ is 45.56 º

4 0
3 years ago
How are scientific theories different than laws or hypotheses?
Gnoma [55]

Answer: Chilling with my homies

Chicken wings, Chicken wings

Hotdog and baloney

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Chilling with mah Chilling with mah

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Chicken chicken chicken chicken chicken wing

Chicken chicken chicken chicken wing

Chicken wings, Chicken wings

Hotdog and baloney

Chicken and macaroni

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Chicken wings, Chicken wings

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Chicken wings, Chicken wings

Hotdog and baloney

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Explanation:

im sorry i had to do it now pls give me brainliest thank u and have a blessed day:)

9 0
3 years ago
Read 2 more answers
To determine the muzzle velocity of a bullet fired from a rifle, you shoot the 2.47-g bullet into a 2.43-kg wooden block. The bl
Elza [17]

Answer:

The velocity of the bullet on leaving the gun's barrel is 236.36 m/s.

Explanation:

Given;

mass of the bullet, m₁ = 2.47 g = 0.00247 kg

mass of the wooden block, m₂ = 2.43 kg

initial velocity of the wooden block, u₂ = 0

height reached by the bullet-block system after collision = 0.295 cm = 0.00295 m

let the initial velocity of the bullet on leaving the gun's barrel = v₁

let final velocity of the bullet-wooden block system after collision = v₂

Apply the principle of conservation of linear momentum;

Total initial momentum = Total final momentum

m₁v₁ + m₂u₂ = v₂(m₁ + m₂)

0.00247v₁  + 2.43 x 0  =  v₂(2.43 + 0.00247)

0.00247v₁ = 2.4325v₂ -------(1)

The kinetic energy of the bullet-block system after collision;

K.E = ¹/₂(m₁ + m₂)v₂²

K.E = ¹/₂ (2.4325)v₂²

The potential energy of the bullet-block system after collision;

P.E = mgh

P.E = (2.4325)(9.8)(0.00295)

P.E = 0.07032

Apply the principle of conservation of mechanical energy;

K.E = P.E

¹/₂ (2.4325)v₂² = 0.07032

1.21625 v₂²  = 0.07032

v₂²  = 0.07032  / 1.21625

v₂² = 0.0578

v₂ = √0.0578

v₂ = 0.24 m/s

Substitute v₂ in equation (1), to obtain the initial velocity of the bullet;

0.00247v₁ = 2.4325v₂

0.00247v₁ = 2.4325 (0.24)

0.00247v₁ = 0.5838

v₁ = 0.5838 / 0.00247

v₁ = 236.36 m/s

Therefore, the velocity of the bullet on leaving the gun's barrel is 236.36 m/s.

5 0
3 years ago
How much force is needed to accelerate a 1-kilogram toy car at a rate of 2 meters per second per second?
kozerog [31]
F = ma,    where m = mass in kg, a = acceleration in m/s², F = Force in Newton

F = 1 * 2

F = 2 N

Force needed is 2 Newtons.
5 0
3 years ago
Read 2 more answers
Find the noise level of a sound having an intensity of 1.5x10^-14W/m^2 given I0=10^12 W/m2
Llana [10]

Answer:

Noise level will be -18.2 watt

So option (b) will be correct answer

Explanation:

We have given sound intensity I=1.5\times 10^{-14}w/m^2

And threshold intensity I_0=\times 10^{-12}w/m^2 ( in question it is given as 10^{12}w/m^2 but its standard value is 10^{-12}w/m^2 )

Now noise level  =10log\frac{I}{I_0}=10log\frac{1.5\times 10^{-14}}{10^{-12}}=10log0.015-18.23

So the noise level will be -18.2

So option (b) will be correct answer

5 0
3 years ago
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