A thin, taut string tied at both ends and oscillating in its third harmonic has its shape described by the equation y(x, t) = (5
1 answer:
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To solve this problem it is necessary to apply the kinematic equations of motion.
By definition we know that the position of a body is given by
Where
Initial position
Initial velocity
a = Acceleration
t= time
And the velocity can be expressed as,
Where,
For our case we have that there is neither initial position nor initial velocity, then
With our values we have , rearranging to find a,
Therefore the final velocity would be
Therefore the final velocity is 81.14m/s
Average acceleration of the baseball:
Explanation:
Since the motion of the baseball is a uniformly accelerated motion, we can use the following suvat equation:
where
u is the initial velocity
v is the final velocity
a is the acceleration
s is the displacement of the object
For the baseball in this problem, we have:
u = 2.2 m/s is the initial velocity
v = 0 is the final velocity (it comes to a stop)
s = 24 mm = 0.024 m is the displacement of the ball while decelerating
Therefore, we can solve for a to find the acceleration:
where the negative sign means the baseball is slowing down.
Learn more about acceleration:
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