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VLD [36.1K]
3 years ago
13

URGENT! Consider the following decomposition reaction of ammonium carbonate ((NH4)2CO3):

Chemistry
1 answer:
dexar [7]3 years ago
6 0
<span>Using PV=nRT to find the moles and then convert back.
</span><span>4x=.8944
</span><span>solve for x then use the pressure for lets say CO2 put that into PV=nRT then solve for n then convert over.
</span>
<span>(.2236)(2)/(298*.08206) = .0183*96g/mol = 1.76g
</span>
<span>For C:

[NH3]^2[CO2][H2O] = Kp
x=0.2236 (2*.2236)^2(.2236)*(.2236)
  =0.001
</span>
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X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the volume of the gaseous mixture was 5.00 L. After the reaction, the volume
vlabodo [156]

Isobaric transition, first law: <span>H=ΔU+w</span> for a gas expansion: <span>w=<span>P<span>ext</span></span>∗ΔV</span> to convert to joules, you need the gas constants. R = 0.08206 L atm/mol*K, R=8.314 J/mol*K <span>w=<span>P<span>ext</span></span>∗ΔV∗<span><span>8.314 J/mol∗K</span><span>0.08206 L atm/mol∗K</span></span></span> <span>ΔU=ΔH−[<span>P<span>ext</span></span>∗ΔV∗<span><span>8.314 J/mol∗K</span><span>0.08206 L atm/mol∗K</span></span>]</span> <span>ΔU=−75000 J−[(43.0atm)∗(2−5)L∗<span><span>8.314 J</span><span>0.08206 L atm</span></span>]</span> Then you need to convert to kJ. by the way U=E, internal energy.
7 0
3 years ago
Minerals with the silicon-oxygen structure shown in Figure 2-1 are classified into what group?
egoroff_w [7]
B----------- oxide is the correct answer
6 0
3 years ago
I am having trouble predicting this equation. "Coke will reduce hot arsenious oxide to pure arsenic (As4). With the 4 as the sub
Rudik [331]
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7 0
3 years ago
True or False: In every gram of sucrose (table sugar) there is 0.513 g of oxygen
Ber [7]

Answer:

True

Explanation:

Step 1: Find molecular formula of sucrose

C₁₂H₂₂O₁₁

Step 2: Convert moles of oxygen present to grams

1 mol O = 16 g O

11 mol O = 176 g O

Step 3: Find molar mass of sucrose

C - 12.01 g/mol

H - 1.01 g/mol

O - 16.00 g/mol

12.01(12) + 22(1.01) + 11(16.00) = 342.34 g/mol C₁₂H₂₂O₁₁

Step 4: Set up dimensional analysis

1 gC_{12}H_{22}O_{11}(\frac{176 gO}{342.34gC_{12}H_{22}O_{11}} )

Step 5: Multiply/Divide and cancel out units

Grams of C₁₂H₂₂O₁₁ and grams of C₁₂H₂₂O₁₁ cancel out.

We are left with grams Oxygen

176/342.34 = 0.514109 grams Oxygen

4 0
3 years ago
Mrs. Nogaki tested four black markers in rubbing alcohol and in water. Each filter paper had four evenly spaced dots. She found
ExtremeBDS [4]

Answer:

Lost pigment of marker when dipped in alcohol

Explanation:

dependent viable = output

so it's the output of what happens after the input.

  • she put the marker in the water which is the independent variable, that's the input
  • the output or the result of that decision is having lost pigment in the marker

8 0
3 years ago
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