Answer: 385.4132857
Explanation:
Using the equation, PV=nRT, you can solve this problem.
P= 3.5 kPa V=? n= 0.55 moles of air T= 295K R= 8.314 (L kPa/mol K)
We use the constant rate of <u>8.314</u> because we are using kilopascals in this problem.
Using simple algebra we get-
V = (0.55 moles)(8.314 L kPa/mol k)(295 K) / 3.5 kPa
Using the calculator, we would get the answer of 385.4132857 L.
And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 liters.
Answer:
Water molecules feature the combinations of hydrogen and oxygen atoms in a 2:1 ratio. Since they are present in a fixed ratio of mass, water molecules obey the law of constant proportions. Water is formed when two molecules of the diatomic hydrogen gas, combine with one molecule of the diatomic oxygen gas to produce two molecules of water
Answer:
it is not correct I have an answer for ''why''
Explanation:
You need to balance it
s= 2
0=2
S+30•2 --------> SO•3
2 2 2 2
S +3O•2-------->SO•2......MULTIPLY
2 4 2 4......LCM IS 4
2 1 2 1....DIVIDE BY 4
SO NOW WE GOT THE BALANCE NO. WE CAN PUT IT IN THE EQUATIONS.
2S+3O•2 -----> 2SO•3
now you can check the both sides its balances the correct answer is this
Answer:
Explanation:
Hello there!
In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:
Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:
Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:
Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:
Then, we accommodate the waters to obtain:
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