Question

A bumblebee has a charge of 1.0 µC is placed 10.0 cm from a charge of 2.5 µC. What is the magnitude of the electric force?

Answer 1

Answer:

F = 2.25 N

Explanation:

Given that,

Charge 1, $q_1=1\ \mu C = 10^{-6}\ C$

Charge 2, $q_2=2.5\ \mu C=2.5\times 10^{-6}\ C$

Distance between charges, d = 10 cm = 0.1 m

We need to find the electric force between charges. The formula that is used to find the electric force is given by

$F=\dfrac{kq_1q_2}{d^2}\\\\F=\dfrac{9\times 10^9\times 10^{-6}\times 2.5\times 10^{-6}}{(0.1)^2}\\\\=2.25\ N$

Hence, the force between charges is 2.25 N.