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rodikova [14]
3 years ago
9

20 points!! Please help ASAP!

Chemistry
1 answer:
Pavel [41]3 years ago
5 0

Answer:

78 ml

Explanation:

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Naphthalene, commonly found in moth balls, is composed of 93.7% carbon and 6.3% hydrogen. The molar mass of naphthalene is 128 g
Vikki [24]

Answer:

Molecular formula naphthalene → C₁₀H₈

Empirical formula naphthalene → C₅H₄

Explanation:

Centesimal composition means that in 100 g of compound we have x g of the element. Therefore in 100 g of naphthalene we have:

93.7 g of C

6.3 g of H

Let's make a rule of three:

In 100 g of naphthalene we have 93.7 g of C  and 6.3 g of H

In 128 g of naphthalene we would have:

128 . 93.7 / 100 = 120 g of C

128.  6.3 / 100 = 8 g of H

We convert the mass to moles, by molar mass:

120 g . 1mol / 12 g = 10 moles C

8 g . 1mol/ 1g = 8 moles H

Molecular formula naphthalene → C₁₀H₈

Empirical formula naphthalene → C₅H₄

(The sub-index of each element is divided by the largest possible number)

6 0
4 years ago
Read 2 more answers
Explain why animals that come out at night have lots of rods in their retina
sesenic [268]

Answer:

Nocturnal animals, such as owls, tend to have wide pupils and several rod cells in their retina because wide pupil allow more light to enter the eyes and the rods cells in the retina are sensitive to dim light and are vital for night vision.

5 0
3 years ago
What are some uses of metals?
VashaNatasha [74]
They are used to make plane bodies.
Some are used for electrical wires eg copper because they are good conductors of electricity.
Used in building materials.
used to make jewelry eg gold and silver<span />
4 0
3 years ago
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If an element has 9 electrons, how many of them will be in the 2nd energy level?
faust18 [17]
Your answer would come out to 18 electrons 
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4 years ago
This is the chemical formula for talc (the main ingredient in talcum powder): mg3(si2o5)2(oh)2. an analytical chemist fins that
weqwewe [10]
In one mole of talc, we observe that there are:
3 moles of Mg
4 moles of Si
2 moles of H
12 moles of O

The molar ratio of O to Mg is then:

12 moles of O : 3 moles of Mg = 4 : 1

Therefore, if 6.1 moles of Mg are present, the moles of O are:

4 * 6.1 = 24.4 moles of O
7 0
3 years ago
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