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emmainna [20.7K]
3 years ago
8

What mass of Al contains the same number of atoms as 33.5g of Au

Chemistry
1 answer:
wel3 years ago
5 0
Stoich questions...

1) convert the grams of Au to moles
(33.5g)/(196.7g/mol)=___x___

2)find how many atoms are in that many moles by multiplying it by avogadro's number.

x(moles of Au)*(6.02*10^23)=?

3)now that you have found the number of atoms of gold, convert it to grams of aluminum by multiplying it by Avogadro's number and multiplying it by the atomic mass of aluminum.
( ? )(6.02*10^23)(26.98g/mol)= (mass of Al)

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Answer:

300K.

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 300L

Initial temperature (T1) = 200K

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Since the pressure is constant, the gas is obeying Charles' law.

Using the Charles' law equation, we can obtain the new temperature of the gas as follow:

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Cross multiply to express in linear form

300 x T2 = 200 x 450

Divide both side by 300

T2 = (200 x 450)/ 300

T2 = 300K

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Answer:

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7 0
3 years ago
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