hi im breanna
Answer:
The mole is simply a very large number that is used by chemists as a unit of measurement.
Explanation:
The mole is simply a very large number,
6.022
×
10
23
, that has a special property. If I have
6.022
×
10
23
hydrogen atoms, I have a mass of 1 gram of hydrogen atoms . If I have
6.022
×
10
23
H
2
molecules, I have a mass of 2 gram of hydrogen molecules. If I have
6.022
×
10
23
C
atoms, I have (approximately!) 12 grams.
The mole is thus the link between the micro world of atoms and molecules, and the macro world of grams and litres, the which we can easily measure by mass or volume. The masses for a mole of each element are given on the periodic table as the atomic weight. So, if have 12 g of
C
, I know, fairly precisely, how many atoms of carbon I have. Given this quantity, I know how many molecules of
O
2
are required to react with the
C
, which I could measure by mass or by volume.
The answer is true, catalysts increase rates by lowering the activation energy of a reaction. Catalysts lower the reaction energy and so the reaction occurs faster. Enzymes perform the role of biological catalysts. Most metabolic pathways of the body are controlled by enzymes. Enzymes by classification are proteins. <span />
Answer:
1.514 moles
Explanation:
For this problem you want to use dimensional analysis and cancel out your molecules of sugar and be left with moles of sugar. We know that 1 mole (of anything) = 6.022 x 10 ^ 23 molecules, so we should use that conversion to help us. Start with 9.12 x 10 ^23 molecules and divide by 6.022 x 10 ^ 23 molecules, and you will be left with moles.
Hope this helps!
Answer:
486 nm
Explanation:
From the question given above, the following data were obtained:
Energy (E) = 4.09×10¯¹⁹ J
Wavelength (λ) =?
Next, we shall determine the frequency of the photon. This can be obtained as follow:
Energy (E) = 4.09×10¯¹⁹ J
Planck's constant (h) = 6.63×10¯³⁴ Js
Frequency (f) =?
E = hf
4.09×10¯¹⁹ = 6.63×10¯³⁴ × f
Divide both side by 6.63×10¯³⁴
f = 4.09×10¯¹⁹ / 6.63×10¯³⁴
f = 6.17×10¹⁴ Hz
Next, we shall determine the wavelength of the photon. This can be obtained as follow:
Frequency (f) = 6.17×10¹⁴ Hz
Velocity of photon (v) = 3×10⁸ m/s
Wavelength (λ) =?
v = λf
3×10⁸ = λ × 6.17×10¹⁴
Divide both side by 6.17×10¹⁴
λ = 3×10⁸ / 6.17×10¹⁴
λ = 4.86×10¯⁷ m
Finally, we shall convert 4.86×10¯⁷ m to nm. This can be obtained as follow:
1 m = 1×10⁹ nm
Therefore,
4.86×10¯⁷ m = 4.86×10¯⁷ m × 1×10⁹ nm / 1 m
4.86×10¯⁷ m = 486 nm
Therefore, the wavelength of the photon is 486 nm
