All categories

3 years ago

When placed 1.18 m apart, the force each exerts on the other is 11.2 N and is repulsive. What is the charge on each

Physics

1 answer:

aleksandr82 [10.1K]3 years ago

7 0

Answer:

$q=41.62\ \mu C$

Explanation:

Given that,

Force between two objects, F = 11.2 N

Distance between objects, d = 1.18 m

We need to find the charge on each objects. The force between charges is as follows :

$F=\dfrac{kq^2}{r^2}\\\\q=\sqrt{\dfrac{Fr^2}{k}} \\\\q=\sqrt{\dfrac{11.2\times (1.18)^2}{9\times 10^9}} \\\\q=41.62\ \mu C$

So, the charge on each sphere is $41.62\ \mu C$ .

You might be interested in

Select all the expressions below which represent a 20% discount off the price of an item that originally costs d dollars.

dmitriy555 [2]

A - 0.8d

multiply the item (d) times 80% (which shows a 20% discount since 100%-20%=80%). Convert 80% to a decimal = .8

therefore, 0.8d

7 0

3 years ago

A tennis ball is shot vertically upward inside a tower with an initial speed of

LenaWriter [7]

The ball's height at time t is

y = (20.0 m/s) t - 1/2 g t²

where g is the acceleration due to gravity, with magnitude 9.80 m/s².

Also, recall that

v² - u² = 2 a ∆y

where u is the initial velocity, v is the final velocity, a is the acceleration, and ∆y is the change in height. Let Y be the maximum height. At this height, v = 0, so

- (20.0 m/s)² = 2 (-g) Y

==> Y ≈ 20.408 m

Plug this into the first equation and solve for t :

Y = (20.0 m/s) t - 1/2 (9.80 m/s²) t²

==> t ≈ 2.04 s

The ball's velocity at time t is

v = 20.0 m/s - g t

After t = 3.0 s, its velocity will be

v = 20.0 m/s - (9.80 m/s²) (3.0 s)

v = -9.40 m/s

or 9.40 m/s in the downward direction.

4 0

3 years ago

Help Easy Question and Brainly. What's the answer?????

denpristay [2]

Answer:

negatively

Explanation:

4 0

3 years ago

Read 2 more answers

If a gun is sighted to hit targets that are at the same height as the gun and 75 m away at the same height, how low, as a positi

Vinvika [58]

Answer:

y=-1.66 m

Explanation:

We know that

Range R

$R=\dfrac{u^2sin2\theta }{g}$

Here given that

u= 275 m/s

R=75 m

Now by putting the values

$R=\dfrac{u^2sin2\theta }{g}$

$35=\dfrac{275^2sin2\theta }{9.81}$

θ=0.13°

Now horizontal component of velocity u will be u cosθ.

Horizontal component = 275 cos0.13 = 274.99 m/s

So the time required to cover 180 m in horizontal direction t

180 = 274.99 x t

t=0.65 sec

Now vertical component of velocity u will be u sinθ.

Horizontal component = 275 sin0.13 = 0.62 m/s

So now vertical displacement y will be

$y=u_yt-\dfrac{1}{2}gt^2$

$y=0.62 \times 0.65-\dfrac{1}{2}\times 9.81\times 0.65^2$

y=-1.66 m

5 0

3 years ago

What is the easiest way to add energy to matter? Heating it Cooling it Decreasing pressure Decreasing temperature

riadik2000 [5.3K]

Answer:heating it

Explanation:

6 0

3 years ago

Read 2 more answers