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Gre4nikov [31]
3 years ago
9

In which type of process is a gas heated so rapidly that is expands before any heat can escape, resulting in an absence of heat

transfer between the gas and the environment? a. isobaric b. adiabatic c. isovolumetric d. isothermal
Physics
1 answer:
aliya0001 [1]3 years ago
3 0

Answer:

Adiabatic.

Explanation:

Any process in which there is no heat tranference is called adiabatic. In the situation, it is explained that due to the change of volume there is no heat between the gas and the environment.

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Pls help meh Kdjdjeidjndiejdididjdjjdidjdjdiejd
Nadya [2.5K]

Answer:

i think b

Explanation:

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6 0
3 years ago
Read 2 more answers
Two force vectors are oriented such that the angle between their directions is 38 degrees and they have the same magnitude. If t
Usimov [2.4K]

Answer:

Sum of the forces will be equal to 3.479 N

Explanation:

We have given two same forces are oriented at an angle of 38°

Magnitude of each force is given F_1=F_2=1.84

We have to find the sum of the forces

Sum of the forces will be equal to

F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\Theta }

So sum of the forces will be equal to F=\sqrt{1.84^2+1.84^2+2\times 1.84\times 1.84\times cos38^{\circ} }=3.479

So sum of the force will be equal to 3.479 N

6 0
3 years ago
Is this charging by induction or conduction?
sineoko [7]
Conduction i believe
3 0
2 years ago
An object of mass 0.40 kg, hanging from a spring with a spring constant of 8.0 N/m, is set into an up-and-down simple harmonic m
Sergeeva-Olga [200]

Answer:

a = 2 m/s2

Explanation:

we know from newtons 2nd law

F = ma.

we also know that from hookes law we have

F = kx

equate both value of force to get value of acceleration

kx = ma,

where,

k is spring constant = 8.0 N/m

x is maximum displacement  0.10 m

m is mass of object 0.40 kg

a = \frac{kx}{m}

     = \frac{8 *0 .10}{0.40}

a = 2 m/s2

5 0
3 years ago
A mass is placed at the end of a spring. It has starting velocity of V & allowed to oscillate freely. If the mass has a star
LiRa [457]

Answer:

Equation for SHM can be written

V = w A cos w t        where w is the angular frequency and the velocity is a                                         maximum at t = 0

V1 = w1  A cos w1 t

V2 = w2 A cos w2 t

V2 / V1 = w2 / w1     since cos X t = 1 if t = zero

V2 / V1 = 2 pi f2 / (2 pi f1) = f2 / f1 = T1 / T2

If the velocity is twice as large the period will be 1/2 long

8 0
3 years ago
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