A student mixed two clear liquids together in a beaker. A solid and a new liquid formed. The student forgot to write down the ma
ss of one of the reactants. The
rest of the data are shown in the table below.
What is the mass of liquid reactant A?
A 1.0 g
B 8.0 g
C 9.0 g
D 11.0 g
E 20.0 g
rest of the data are shown in the table below.
What is the mass of liquid reactant A?
A 1.0 g
B 8.0 g
C 9.0 g
D 11.0 g
E 20.0 g
1 answer:
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Answer:
63.5 °C
Explanation:
The expression for the calculation of work done is shown below as:
Where, P is the pressure
is the change in volume
Also,
Considering the ideal gas equation as:-
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 8.314 J/ K mol
So,
Also, for change in volume at constant pressure, the above equation can be written as;-
So, putting in the expression of the work done, we get that:-
Given, initial temperature = 28.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (28.0 + 273.15) K = 301.15 K
W=1770 J
n = 6 moles
So,
Thus,
The temperature in Celsius = 336.63-273.15 °C = 63.5 °C
<u>The final temperature is:- 63.5 °C</u>
This question is incomplete, the missing image is uploaded along this answer below.
Answer:
the speed of the 50-kg cylinder after it has descended is 3.67 m/s
Explanation:
Given the data in the question and the image below;
relation between velocity of cylinder and velocity of the drum is;
V = ω
× r
----- let this be equ 1
where V is velocity of cylinder, ω
is the angular velocity of drum C and r
is the radius of drum C
Now, Angular velocity of gear B is;
ω = ω
ω = V
/ r
-------- let this equ 2
so;
V / 0.1 m = 10V
Next, we determine the angular velocity of gear A;
from the diagram;
ω( 0.15 m ) = ω
( 0.2 m )
from equation 2; ω = V
/ r
so
ω( 0.15 m ) = (V
/ r
) 0.2 m
substitutive in value of radius r (0.1 m)
ω( 0.15 m ) = (V
/ 0.1 m ) 0.2 m
ω( 0.15 ) = 0.2V
/ 0.1
ω = 2V
/ 0.15
ω = 13.333V
----- let this be equation 3
To get the speed of the cylinder, we use energy conversation;
assuming that the final position is;
T₁ + ∑ = T₂
0 + mgh =
m
V²
+
ω²
+
ω²
so
mgh =
m
V²
+
(m
k
²)(13.333V
)² +
(m
k
²)(10V
)²
we given that; m = 50 kg, h = 2 m, m
= 10 kg, k
125 mm = 0.125 m, m
= 30 kg, k
= 150 mm = 0.15 m.
we know that; g = 9.81 m/s²
so we substitute
50 × 9.81 × 2 = ( × 50 × V
²) +
( 10 × (0.125)² )(13.333V
)² +
( 30 × (0.15)²)(10V
)²
981 = 25V² + 13.888V
² + 33.75V
²
981 = 72.638V²
V² = 981 / 72.638
V² = 13.5053
V = √13.5053
V = 3.674955 ≈ 3.67 m/s
Therefore, the speed of the 50-kg cylinder after it has descended is 3.67 m/s
Answer:
B. parents
Explanation:
one of the conclusions from Einsteins relativity theory for his equation E= (where E is energy, m is mass and C is the speed of light),
is that time moves relative to the observer. Time moves more slowly when the observer is in motion (time dilation), therefore an individual in motion ages more slowly than someone at rest. This in fact happened when astronaut Scot Kelly spent nearly a year on board the international space station and on his return, his twin brother had aged slightly faster than him. In conclusion, if a space trip finds a son or daughter is biologically older than his or her parents, the space trip was taken by the parents.