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Oxana [17]
2 years ago
8

A student mixed two clear liquids together in a beaker. A solid and a new liquid formed. The student forgot to write down the ma

ss of one of the reactants. The
rest of the data are shown in the table below.

What is the mass of liquid reactant A?
A 1.0 g
B 8.0 g
C 9.0 g
D 11.0 g
E 20.0 g

Physics
1 answer:
ziro4ka [17]2 years ago
3 0
The answer to the question is probably A
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bixtya [17]

Answer:Force on -7 uC charge due to charge placed at x = - 10cm

now we will have

towards left

similarly force due to -5 uC charge placed at x = 6 cm

now we will have

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Now net force on 7 uC charge is given as

towards left

Explanation:

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3 years ago
1:A pattern or grouping of stars that people imagine representing a figure, an animal or an object.
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Answer:

  • 1.constellation
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Identify one common cuase of the inreasing of overweight and obese people in the United States
amid [387]

The most common one is junk food and sugary snacks are very very addicting! they are almost like drugs!!!

4 0
3 years ago
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In a playground, there is a small merry-go-round of radius 1.20 m and mass 160 kg. Its radius of gyration is 91.0 cm. (Radius of
aksik [14]

Answer:

a) 145.6kgm^2

b) 158.4kg-m^2/s

c) 0.76rads/s

Explanation:

Complete qestion: a) the rotational inertia of the merry-go-round about its axis of rotation 

(b) the magnitude of the angular momentum of the child, while running, about the axis of rotation of the merry-go-round and

(c) the angular speed of the merry-go-round and child after the child has jumped on.

a) From I = MK^2

I = (160Kg)(0.91m)^2

I = 145.6kgm^2

b) The magnitude of the angular momentum is given by:

L= r × p The raduis and momentum are perpendicular.

L = r × mc

L = (1.20m)(44.0kg)(3.0m/s)

L = 158.4kg-m^2/s

c) The total moment of inertia comprises of the merry- go - round and the child. the angular speed is given by:

L = Iw

158.4kgm^2/s = [145kgm^2 + ( 44.0kg)(1.20)^2]

w = 158.6/208.96

w = 0.76rad/s

7 0
3 years ago
400 N of load can be overcome by an effort of 50 N by using a lever. Calculate the mechanical advantage of the lever.
mars1129 [50]

Answer:

load (l)=400N

Effort(E)=50N

mechanical advantage (MA)= load ÷Effort

(ma)=400÷50

(ma)=8

Explanation:

I copy pasted from the answer from the same question. Remember to first check if ur question is there

4 0
3 years ago
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