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stepan [7]
3 years ago
11

A 150 g ceramic serving bowl is warmed 52.0°C when it absorbs 2.2 kcal of heat from a serving of hot food. What is the specific

heat of the china dish?
Physics
1 answer:
allochka39001 [22]3 years ago
8 0

Answer:

1.18010256J/Kg°C

Explanation:

The quantity of heat energy is expressed as:

Q = mct

c is the specific heat capacity

t is change in temperature

Q = 4.184×2.2

Q = 9.2048Joules

m = 150g = 0.15kg

t = 52°C

Substitute and get c

9.2048 = 0.15c(52)

9.2048 = 7.8c

c = 9.2048/7.8

c = 1.18010256

Hence the specific heat capacity of the dish is 1.18010256J/Kg°C

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Answer:

Part a)

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Part b)

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Explanation:

Part a)

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Part b)

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Fcos\theta = mg - \mu(Fsin\theta)

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F = \frac{mg}{cos\theta + \mu sin\theta}

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F = 62.5 N

6 0
3 years ago
When a potential difference of 13 V is placed across a resistor, the current in the resistor is 1.4
vitfil [10]
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This is a conservation of momentum problem! Here's how to do it:

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Explanation:

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Answer:

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Explanation:

8 0
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