<h3>
Answer:</h3>
1.926 g of NaOH
<h3>
Explanation:</h3>
Concept tested: Mole and Avogadro's number
- We need to know that , 1 mole of a compound contains number of molecules equivalent to the Avogadro's number.
- Th Avogadro's number is 6.022 × 10^23
Therefore;
- 1 mole of a compound = 6.022 × 10^23 molecules
In this case; Our compound is NaOH
Therefore;
1 mole of NaOH contains 6.022 × 10^23 molecules
But; Molar mass of NaOH is 40.0 g/mol
Therefore;
- 40.0 g of NaOH contains 6.022 × 10^23 molecules
With this we can calculate the mass of 2.90 × 10^22 molecules
- Mass of a compound = (number of molecules ÷ Avogadro's constant) × molar mass
Therefore;
Mass of NaOH =(2.90 × 10^22 molecules ÷ 6.022 × 10^23 molecules)40g
= 1.9263 g
= 1.926 g NaOH
Thus, the mass of NaOH is 1.926 g
Hello!
First, we need to determine the pKa of the base. It can be found applying the following equation:

Now, we can apply the
Henderson-Hasselbach's equation in the following way:
![pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%20%5Cfrac%7B%5BCH_3NH_2%5D%7D%7B%5BCH_3NH_3Cl%5D%7D%20%29%3D10%2C65%2Blog%28%20%5Cfrac%7B0%2C18M%7D%7B0%2C73M%7D%20%29%3D10%2C04)
So,
the pH of this buffer solution is 10,04Have a nice day!
A solution's pH will be a number between 0 and 14. A solution with a pH of 7 is classified as neutral. If the pH is lower than 7, the solution is acidic. When pH is higher than 7, the solution is basic. These numbers describe the concentration of hydrogen ions in the solution and increase on a negative logarithmic scale. For example, If Solution A has a pH of 3 and Solution B has a pH of 1, then Solution B has 100 times as many hydrogen ions than A and is therefore 100 times more acidic.
The balanced chemical equation between HCl and
is:

Moles of
= 
Moles of HCl required to neutralize
:

Calculating the volume of HCl from moles and molarity:

Answer:

Explanation:
In beta emission, a neutron is converted into a proton thereby reducing the neutron:proton (N/P) ratio.
When a beta emission occurs, the mass number remains the same while the nuclear charge increases by one unit. The daughter nucleus is found one place to the right of its parent in the periodic table.