Question

How many atoms are in 4.00 moles of helium?

Answer 1

Answer:

Number of atoms in 4.00 moles of helium = $2.4092\times 10^{24}$

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by $N_0$.

Avogadro constant:-

$N_a=6.023\times 10^{23}$

Thus,

1 mole of helium contains  $6.023\times 10^{23}$ atoms

So,

4.00 moles of helium contains  $4.00\times 6.023\times 10^{23}$ atoms

Number of atoms in 4.00 moles of helium = $2.4092\times 10^{24}$

Answer 2

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

4 mol He (  6.022 x 10^23 atoms / mole ) = 2.4088 x 10^34 atoms He