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3 years ago

The weight of a box is found to be 30 N. What is the approximate mass of the box?

Physics

2 answers:

diamong [38]3 years ago

8 0

Answer:

3 or 3.6 kg

Explanation:

This question is basically asking you to convert Newtons to kilograms. Which you may simply go to this converting website: https://www.traditionaloven.com/culinary-arts/weight/convert-newton-earth-n-to-kilogram-kg.html

to figure it out ♥

KengaRu [80]3 years ago

3 0

The mass of the box would be 30!

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Answer:

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2 years ago

To determine an athlete's body fat, she is weighed first in air and then again while she's completely underwater. it is found th

il63 [147K]

The difference in weight is due to the displacement of water (the buoyancy of water is acting on the athlete thus giving her smaller weight).<span>

The amount of weight displaced or the amount of buoyant force is: </span>

Fb = 690 N - 48 N

Fb = 642 N

From newtons law, F = m*g. Using this formula, we can calculate for the mass of water displaced:

m of water displaced = 642N / 9.8m/s^2

m of water displaced = 65.5 kg

Assuming a water density of 1 kg/L, and using the formula volume = mass/density:

V of water displaced = 65.5kg / 1kg/L = 65.5 L

The volume of water displaced is equal to the volume of athlete. Therefore:

V of athlete = 65.5 L

The mass of athlete can also be calculated using, F = m*g

m of athlete = 690 N/ 9.8m/s^2

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Knowing the volume and mass of athlete, her average density is therefore:

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3 years ago

Read 2 more answers

Scientific theories are deductive in nature.?

dolphi86 [110]

Answer:

deductive reasoning usually follows steps .

That is, how we predict what the observations should be if the theory were correct

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2 years ago

A ball is dropped from rest at the top of a 6.10 m

natita [175]

Answer:

n = 5 approx

Explanation:

If v be the velocity before the contact with the ground and v₁ be the velocity of bouncing back

$\frac{v_1}{v}$ = e ( coefficient of restitution ) = $\frac{1}{\sqrt{10} }$

and

$\frac{v_1}{v} = \sqrt{\frac{h_1}{6.1} }$

h₁ is height up-to which the ball bounces back after first bounce.

From the two equations we can write that

$e = \sqrt{\frac{h_1}{6.1} }$

$e = \sqrt{\frac{h_2}{h_1} }$

So on

$e^n = \sqrt{\frac{h_1}{6.1} }\times \sqrt{\frac{h_2}{h_1} }\times... \sqrt{\frac{h_n}{h_{n-1} }$

$(\frac{1}{\sqrt{10} })^n=\frac{2.38}{6.1}$ = .00396

Taking log on both sides

- n / 2 = log .00396

n / 2 = 2.4

n = 5 approx

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2 years ago

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grandymaker [24]

Answer:

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3 years ago