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barxatty [35]
3 years ago
11

Convert 2 1/5 to an improper fraction.

Mathematics
2 answers:
DochEvi [55]3 years ago
3 0

Answer: 11/5

Step-by-step explanation:

you would do (2) times (5) to get 10.

then you'd add 1+10 to get 11.

write this new number as the numerator... 11/5.

PilotLPTM [1.2K]3 years ago
3 0

Answer:

11/5

Step-by-step explanation:

multiply the whole number (2) to the denominator (5) which will give you 10 then add the numerator (1) to it which will give you 11, and always keep the denominator which here is 5.

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Find the missing length indicated
NNADVOKAT [17]

Answer:

x = 240

Step-by-step explanation:

Using the Altitude- on- Hypotenuse theorem

(leg of large triangle)² = ( part of hypotenuse below it) × (whole hypotenuse)

x² = 144 × 400 = 57600 ( take the square root of both sides )

x = \sqrt{57600} = 240

7 0
3 years ago
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While at the zoo, you saw 20 monkeys in an exhibit. Then some of the monkeys go and hide while the zoo keeper moves 5 monkeys to
Vladimir79 [104]

It would be 7.

Because 20-5-15 then 15-8=7

7 0
3 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
3 years ago
Let f (x) = 10 x^10 – 5x^8 +2x^6
swat32
This question is way to hard
8 0
3 years ago
What is the sum of 2/5 and 1/3
VladimirAG [237]

Answer:11/15

Step-by-step explanation:

Most common denominator is 15 multiply 2/5 by 3 and 1/3 by 5 and that’s what you get

7 0
4 years ago
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