Answer:
the charge generated in the circuit is 240 C.
Explanation:
Given;
current flowing in the circuit, I = 2A
time of current flow, t = 2 minutes = 2 x 60s = 120 s
The current flowing through a given circuit is defined as the quantity of charge flowing through the circuit in a given time.
where;
Q is the charge flowing in the circuit
Q = 2 x 120
Q = 240 C
Therefore, the charge generated in the circuit is 240 C.
Ability to memorize and regurgitate information on tests is the skill that can’t help a person to thrive today in this modern 21st century.
Answer: Option D
<u>Explanation:</u>
Thriving in this modern 21st century is not as easy as it used to be in the early 20th and 19th centuries. So there is a need to develop skills like implementing one's knowledge to real-world structures which will sure help a person to understand and explore more.
Statement B also will sure be helpful to survive in modern society and a person can also improve his/her critical thinking, problem solving and other skills to thrive through this century.
But even though memorizing and regurgitating information can help you get good grade it will never be that helpful in other ways, So option D can be concluded as the right answer.
We assume that the gas is an ideal gas so we can use the relation PV=nRT. Assuming that the temperature of the system is at ambient temperature, T = 298 K. We can calculate as follows:
PV = nRT
P = nRT / V
P = (0.801 mol ) (0.08205 L-atm / mol-K) (298.15 K) / 12 L
P = 1.633 atm
Answer:
the answer is b
Explanation:
I continues to,increase than decrease
<span>Let t =0 Q=Qmax I=0 Energy stored in the capacitor in a LC circuit is Umax = Qmax^2/ 2c where Qmax is the initial charge stored in a capacitor.
</span><span>
</span><span> When energy is equally shared between a capacitor and inductor, the energy stored in the capacitor becomes U = Q^2/2c .
</span><span>
</span><span>According to the given condition , energy is equally shared between an inductor and capacitor, the energy stored in the capacitor becomes half of the initial energy.
</span><span>
</span><span>Therefore, U = 1/2Umax Q^2/2c = 1/2 Qmax^2/2c Q^2 = 1/2 Qmax^2 Q = Qmax / square root 2</span>
