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krok68 [10]
3 years ago
10

Represent the arithmetic series using the recursive formula. 94, 89, 84, 79, … pLeAsE hUrRy

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0

Answer:

The answer is 5

Step-by-step explanation:

Hope it helps <3 c:

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During a sale, 20-cent candy bars were sold at 3 for 50 cents. How much is saved on 9 bars?
Mazyrski [523]

Answer:

Step-by-step explanation:

$0.30

Step-by-step explanation:

1 bar of candy = $0.20

3 bars of candy = $0.50

To solve, multiply for both:

If you pay for each candy bar individually, they each cost $0.20. Multiply 9 with 0.20:

9 x 0.20 = $1.80

If you pay for the candy bars by 3's, they cost $0.50 each pack. Divide 9 with 3, then multiply by 0.50:

9/3 = 3

3 x 0.50 = $1.50

Subtract the total cost of the individual from the pack:

$1.80 - $1.50 = $0.30

. $0.30 is your answer.

8 0
3 years ago
(–23) – 45 – (–98) = ?
lisabon 2012 [21]
(–23) – 45 – (–98) =–23 – 45 +98=-68+98=30
6 0
3 years ago
Read 2 more answers
Ayuda plis es para hoy​
aivan3 [116]
Es la segunda media es 1.65, mediana es 1.65, y modo es 1.61
5 0
3 years ago
What is the distance from the point (a, −b, −4) to the origin?
laiz [17]

Answer:

  \sqrt{a^2+b^2+16}

Step-by-step explanation:

The distance (d) between two points in 3 dimensions is ...

  d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

Then the distance between (a, -b, -4) and (0, 0, 0) is ...

  d = √((a -0)² +(-b -0)² +(-4 -0)²)

  = √(a² +b² +16)

6 0
3 years ago
We can describe 15×-10 as an expression. we would describe 6×-2&lt; 35 as an...
algol [13]

Answer: Inequality

Step-by-step explanation:

From the question, if we can describe 15×-10 as an expression, then we would describe 6×-2< 35 as an inequality. An

inequality is used to compare two values, and shows if one is less than, or greater than, or maybe not equal to the other value.

For example, a ≠ b means that a is not equal to b and a < b means a is less than b while a > b means a is greater than b. From the question, 6×-2< 35 means that 6x - 2 is less than 35.

8 0
3 years ago
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