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3 years ago

Evauluate 37/100+3/10

Mathematics

2 answers:

Ad libitum [116K]3 years ago

8 0

Answer:

67/100

Step-by-step explanation:

37/100+3/10

Get a common denominator

37/100 + 3/10 *10/10

37/100+30/100

67/100

zheka24 [161]3 years ago

4 0

Answer:

67/100

Step-by-step explanation:

Find common denominators, note that what you do to the denominator, you must do to the numerator.

The common denominator is 100:

(3/10)(10/10) = (3 * 10)/(10 * 10) = 30/100

Add:

37/100 + 30/100 = 67/100

67/100 is your answer.

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Hunter did not want to spend more than 150$ for a flight from Reno to Los Angeles. Write the inequality that models this situati

Jobisdone [24]

Answer:

$(a)\ x < 150$

$(b)\ x = 149; x = 148$

Step-by-step explanation:

Given

$Amount = 150$ --- not more than

$x \to$ spending

Solving (a): Represent as an inequality

Not more than means <

So, the inequality is:

$Spending < Amount$

$x < 150$

Solving (b): The first two possible solutions

These are the numbers closest to 150 i.e. 149 and 148

Hence, $x = 149; x = 148$

7 0

3 years ago

Multiply me by 4 then subtract 13 if you divide me by 3 and add 17 you get 22

8_murik_8 [283]

You have to do the opposite

22-17=5
5x3=15
15+13=28
28/4=7

The answer is 7. You can check this by doing what it says and if it makes 22, it’s correct. (I’ve already checked it) :)

6 0

3 years ago

How do you graph this?

Gemiola [76]

Answer:

You need more information to graaph this.

Step-by-step explanation:

6 0

3 years ago

Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6

Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" = [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL = 0 ( SET TO ZERO )

Diagram of the Chart uploaded below

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0 ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0

3 years ago

An engineer is going to redesign an ejection seat for an airplane. the seat was designed for pilots weighing between 130lb and 1

Vlad [161]

Answer: 0.4758

Step-by-step explanation:

Given : Mean : $\mu=137\text{ lb}$

Standard deviation : $\sigma =28.9\text{ lb}$

Also, the new population of pilots has normally distributed .

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x=130 lb .

$z=\dfrac{130-137}{28.9}=-0.2422145\approx-0.24$

For x=171lb.

$z=\dfrac{171-137}{28.9}=1.1764705\approx1.18$

The p-value = $P(-0.24$

$=0.8809999-0.4051651=0.4758348\approx0.4758348\approx0.4758$

Hence, the required probability : 0.4758

6 0

3 years ago