You can use the distance formula
Sqroot((x2-x1)^2 + (y2-y1)^2)
(2,-1) and (5,3), use given points
Sqroot((5-2)^2 + (3-(-1))^2)
Sqroot((3)^2 + (4^2)
Sqroot(9+16) = squareroot of 25

Squareroot of 25 = 5

Solution: D. 5 units

4 0

2 years ago

The area of a circle is equal to the area of a square measuring 5 centimeters on each side find the radius of the circle

Gre4nikov [31]

The area os the square is 25 cm sq so the radius of the circle should be about 2.82 cm

4 0

3 years ago

**PLEASE HELP ASAP** Terri is analyzing a circle, y^2 + x^2 = 36, and a linear function g(x). Will they intersect?

Alborosie

We analyze the linear function to find that it has equation $y=x$ . Drawing the line, we find that it will intersect the circle at negative and positive x-coordinates.

We can prove this by substituting $y=x$ into the given equation:

$x^2+x^2=36$

$2x^2=36$

$x^2 = 18$

$x = \pm 3\sqrt{2}$

Hence, $x = 3\sqrt{2}$ or $-\sqrt{2}$ , so there are both positive and negative values for $x$ .

5 0

3 years ago

Find the remainder when x^5-x-1 is divided by (x-1)(x-2)​

Find the remainder when x^5-x-1 is divided by (x-1)(x-2)