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marta [7]
3 years ago
15

Find the remainder when x^5-x-1 is divided by (x-1)(x-2)​

Mathematics
1 answer:
Elina [12.6K]3 years ago
6 0

Answer:

ldk Sry

Step-by-step explanation:

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The length of a planet's orbit around a star is approximately 29,870,000 km.
Sliva [168]

Answer:

745 k/hr

Step-by-step explanation:

mathematically, 1 day = 24 hours

1670 days = 1670 * 24 = 40,080 hours

The speed is thus;

(29,870,000)/40,080 = 745.259

= 745 km/h

5 0
2 years ago
Tina ordered a pizza for lunch. The pizza is round and has a radius of 8 inches. Tina only ate 13 of the pizza and took home the
Alex Ar [27]

Correction

brainly.com/question/15712098

Answer:

67.02\ in^2

Step-by-step explanation:

-We find the surface area of the formula as follows:

A=\pi r^2, \ \ r=radius=8\ in\\\\=\pi \times 8^2\\\\=201.06\ in^2

#We then find the area of the remaining fraction if she only ate one third:

Eaten=\frac{1}{3}\times Area\\\\=\frac{1}{3}\times 201.06\ in^2\\\\=67.02\ in^2

Hence, Tina ate 67.02\ in^2 of the pizza.

3 0
2 years ago
Burke Middle School has an $80 budget to stock the concession stand with drinks at the spring play. Each drink costs the school
serious [3.7K]

Answer:

21

Step-dream ):)

6 0
3 years ago
Read 2 more answers
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
____ regular polygons are symmetrical.
Zielflug [23.3K]
D, all apply
You can cut all in half and they will be equal
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3 years ago
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