3. g(x) = (x+2)/ |x+2| the denominator cannot be 0
|x+2| cannot be 0
x cannot equal -2
Domain all real numbers but -2
g(-1) = (-1+2)/ |-1+2| = 1/|1| = 1
4. h(x) = (x-4)/(x^2+5x-36)
factor the denominator
h(x) = (x-4)/(x+9) (x-4) the denominator cannot be zero do not cancel, this is a hole
x+9 cannot equal zero so x cannot equal -9
x-4 cannot equal 0 so x cannot equal 4
Domain all real numbers but -9 and 4
h(-1) = (-1-4)/((-1)^2+5(-1)-36) = -5/(1-5-36) = -5/-40 = 1/8
Answer: (-2,-1)
Step-by-step explanation:
A and B are the endpoints and we know that to find the midpoint, we need to find the average between the x and y values.
The x coordinate of A plus the x coordinate of B has to equal 0. We can represent that by the equation
now solve for x to find the x coordinate of B by first multiplying both sides by 2.
x + 2 = 0 Subtract 2 from both sides
-2 -2
x = -2
So the x coordinate is -2 now find the y coordinate using the same method.
Multiply both sides by 2
-5 +y = -6 Add -5 to both sides
+5 +5
y = -1
The y coordinate is -1
so the coordinates of B is (-2,-1)
One way they are similar, is that they are both 3-Dimentional figures.
Hope this helps!