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coldgirl [10]
2 years ago
6

Which chemical symbol represents an element?

Chemistry
2 answers:
stellarik [79]2 years ago
4 0
CO because it is the chemical symbol for the element cobalt whereas the rest are compound. H20 is water, CO2 is carbon dioxide and N2 is dinitrogen.
emmasim [6.3K]2 years ago
3 0

Answer: N_2

Explanation:

Element is a pure substance which is composed of atoms of similar elements.

It can not be decomposed into simpler constituents using chemical reactions.Example: Nitrogen (N_2)

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.

It can be decomposed into simpler constituents using chemical reactions. Example: carbon dioxide (CO_2) , water (H_2O), carbon monoxide (CO)

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state the conditions under which copper reacts with sulphuric (vi) acid and give an equation for the reaction​
uranmaximum [27]

Answer:

When the metal reacts with hot, concentrated sulphuric acid, the products of the reaction are copper (II) sulphate, sulphur dioxide and water. Cu + 2H2SO4 = CuSO4 + SO2 + 2H2O. This is a typical redox reaction in which the acid is reduced to SO2, but no hydrogen is produced here

3 0
2 years ago
At 0 degrees Celsius, a gas occupies 22.4L. How hot must the gas be in celcius to reach a volume of 25.0L
NikAS [45]

Answer:

31.7 °C

Explanation:

Charles law states that for volume of a gas is directly proportional to the absolute temperature for a fixed amount of gas at constant pressure

we can use the following equation

V1/T1 = V2/T2

where V1 is volume and T1 is temperature at first instance

V2 is volume and T2 is temperature at second instance

temperature should be in kelvin scale

T1 - 0 °C + 273 = 273 K

substituting the values in the equation

22.4 L / 273 K = 25.0 L / T2

T2 = 304.7 K

temperature in celcius is - 304.7 K - 273 = 31.7 °C

the gas must be 31.7 °C to reach a volume of 25.0 L

7 0
2 years ago
As a result of the gold foil experiment, it was concluded that an atom(1) contains protons, neutrons, and electrons(2) contains
grin007 [14]
The answer is (2). If you recall Rutherford's gold foil experiment, remember that a stream of positively charged alpha particles were shot at a gold foil in the center of a detector ring. The important observation was that although most of the particles passed straight through the foil without being deflected, a tiny fraction of the alpha particles were deflected off the axis of the shot, and some were even deflected almost back to the point from which they were shot. The fact that some of the alpha particles were deflected indicated a positive charge (because same charges repel), and the fact that only a small fraction of the particles were deflected indicated that the positive charge was concentrated in a small area, probably residing at the center of the atom.
8 0
2 years ago
PLEASE HELPP!!!!
Alenkinab [10]

Answer:

Na the valency electrons is 1

The ion charge is positive 1

K the valency electrons is 1

The ion charge is positive 1

Explanation:

Mg the valency electron is 2 The ion charge is positive 2

Ca the valency electron is 2 The ion charge is positive 2

Al the valency electron is 3 The ion charge is positive 3

O the valency electron is 2 The ion charge

is negative 2

F the valency electron is 1 The ion charge is negative 1

Cl the valency electron is 1 The ion charge

is negative 1

N the valency electron is 3 The ion charge is negative 3

S the valency electron is 2 The ion charge is

negative 2

3 0
3 years ago
According to the balanced equation shown below, 1.00 mole of oxalic acid, h2c2o4, reacts with _________ moles of permanganate io
zheka24 [161]
The balanced equation that shows the reaction between oxalic acid and permanganate ion in an acidic medium is: 2MnO4- + 5H2C2O4 + 6H+ -> 2Mn(2+) + 10CO2 + 8H2O. Thus, 1 mole of oxalic acid reacts with 0.4 mole of permanganate ion. This was obtained using stoichiometry:

1 mol H2C2O4 x (2 mol MnO4-/ 5 mol H2C2O4) = 0.4 mol MnO4- 

In this redox reaction, the permanganate is reduced to manganese(II) ion.
6 0
3 years ago
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