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RoseWind [281]
3 years ago
6

Please help me with this math problem. Thank you :)) brainliest if your correct!

Mathematics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

x + 2

Step-by-step explanation:

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Please give me the correct answer.Only answer if you're very good at math.​
Margaret [11]

Answer:

M is negative

Step-by-step explanation:

6 0
2 years ago
Please please help me
enyata [817]

The area of a parallelogram is given by

A=bh

Now, if we consider the 9.9 inches side as the base, then the height is the one labeled with 5.5 inches.

If instead we choose the 11 inches side as the base, the height is h.

So, we can express the area in this two equivalent ways:

A = 9.9\cdot 5.5 = 11\cdot h

Solving for h, we have

h = \dfrac{9.9\cdot 5.5}{11} = 4.95

8 0
3 years ago
Come up with an example for a solid, liquid, and gas describing the particle movement.
Volgvan

Answer:

Ice Cube, Liquid Water, and Steam

Step-by-step explanation:

An example of a solid is a ice cube, the particles are compacted together and there's very little movement.

An example of a liquid is water, the particles are more spread around and the movement is more frequent.

An example of a gas is steam, the particles are anywhere, moving fast and sporadic.

3 0
2 years ago
11000 is compounded semiannually at a rate of 12% for 21 years. Find the total amount in the compound interest account
marishachu [46]

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\dotfill &\$11000\\
r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus twice}
\end{array}\dotfill &2\\
t=years\dotfill &21
\end{cases}


\bf A=11000\left(1+\frac{0.12}{2}\right)^{2\cdot 21}\implies A=11000(1.06)^{42}\implies A\approx 127127.359416

5 0
3 years ago
Algebra help please
leva [86]
The value of a would be 4.2, because the negatives cancel out each other.
4 0
3 years ago
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