3 years ago

A runner having mass of 55 kg moving at a speed of 9 m/s rounds a bend with a radius of 18 m. What is the centripetal

Physics

1 answer:

nikklg [1K]3 years ago

7 0

Answer:

centripetal acceleration = 4.5 m/s^2 ; centripetal force = 247.5 N

Explanation:

centripetal acceleration = v^2 / r = 9^2 / 18 = 4.5 m/s^2

centripetal force = mv^2 / r = 4.5 x 55 = 247.5 N

You might be interested in

The force on the spring is F0 and it stores elastic potential energy PEs0. If the spring displacement is tripled to 3x0, determi

Dimas [21]

Answer:

Explanation:

Let initial extension in the spring= x₀

Force on the spring = F₀

Let spring constant = k

Fo = k x₀

Fn = 3k x₀

Fn /Fo = 3

PEs0 ( ORIGINAL) =1/2 k x₀²

PEsn ( NEW) =1/2 k (3x₀)²

PEsn / PEs0 = 9

7 0

3 years ago

Is a Joule the same as a Kelvin?

earnstyle [38]

No,because a Kevin is 7.242971666663E+22 times Smaller than a Joule.

7 0

3 years ago

Read 2 more answers

I run around a circular track, with radius 25m, for 4 and times before stopping. It takes me 16

Sergio039 [100]

Answer:

13m/s. is the answer probably but do u have ms gallup too?

4 0

3 years ago

Which shapes / structures are more stable?

NeX [460]

Most often those smaller structures are triangular in shape because triangular shapes are very strong and stable

3 0

3 years ago

Read 2 more answers

A 250 g block of ice is removed from the refrigerator at -8.0°C. How much thermal energy does the ice absorb as it warms to room

zlopas [31]

Answer:

Q = 114895 J

Explanation:

To find the thermal energy gained by the ice you use the following formula:

$Q=mc(T_2-T_1)+H_f\ m$

m: mass of the ice = 0.250kg

T2: final temperature = 22°C

T1: initial temperature = -8.0°C

Hf: heat of fusion of water = 3.34*10^5 J/kg

c: specific heat of water = 4186 J/kg

By replacing the values of the parameters you have:

$Q=(0.250kg)(4186J/kg\°C)(22+8)\°C+(3.34*10^5 J/kg)(0.250kg)\\\\Q=114895\ J$

where you have considered that ice melts completely

3 0

3 years ago