F(n)=4n+1 seems to be the basic function for these sets.
Answer:
5/13 for Todd running next day if this helps?
I counted the days and then counted 13 was the total so it is 5/13
Step-by-step explanation:
Days = 2,+3,+3,+ 5 = 13
13= 5/13 = probability
13 = 8:5 = ratio
5/13 was the probability of the results reoccurring same as day 5
Just as results being under 3km would only be 2/13
The 5 people can seat in a row in 5! ways
But we need to exclude the ways <span>that ann and bob are seated next to each other which is = 4! * 2!
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So, the number of <span>ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72
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<span>Another solution:
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<span>If ann seated in one of the ends, the number of ways = 3*2
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<span>If ann didn't seat in one of the ends , the number of ways = 2*3
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So, the total number of <span>ways that can <span>ann, bob be seated = 3*2 + 2*3 = 12
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The remaining persons can seat with a number of ways = 3! = 6
So, the total ways that the five persons can seat = 12*6 = 72
Its being dilated by 3 therefore your answer is 9.9
0.5 is 50%
0.12 is 12%
0.155 is 15.5%