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3 years ago

What would happen if all the waste that the earth produces was put into space would that have a positive or negative effect

1 answer:

6 0

Negative... it would then be in space and eventually killing us for
1.) it could block the sun and we would slowly freeze to death
and 2.) it could one day find its way back into earth and comes casing into the earth casing a meager food chain mouth-function.
i suck at spelling just fyi.

You might be interested in

How does the Earth's rotation affect our view of stars?

rodikova [14]

you only see the stars once every twenty for hours so you can have daylight so because of Earth's rotation you only see the stars for a certain amount of hours

Explanation:

the Earth makes a full rotation so that's why my answer is what it is

5 0

2 years ago

The diagram does not represent a real electric field because the field lines__<br> NEED ANSWERS NOW

prohojiy [21]

Answer:

cross at many points

Explanation:

According to the diagram it does not shows the real electric field as the electric field does not intersect with each other but according to the given diagram many lines are intersected with each other

So the correct option is C as it would be crossed at many points

Hence, the same would be relevant

6 0

2 years ago

Helium–neon laser light (λ = 632.8 nm) is sent through a 0.350-mm-wide single slit. What is the width of the central maximum on

Cloud [144]

Answer:

The width of the central bright fringe is 7.24 mm.

Explanation:

Given that,

Wavelength = 632.8 nm

Width d= 0.350 mm

Distance between screen and slit D= 2.00 m

We need to calculate the distance

Using formula of distance

$y_{m}=\dfrac{\lambda D}{d}$

Put the value into the formula

$y_{m}=\dfrac{632.8\times10^{-9}\times2.00}{0.350\times10^{-3}}$

$y_{m}=3.62\ mm$

We need to calculate the width of the central bright fringe

Using formula of width

$width = 2\times|y_{m}|$

Put the value into the formula

$width=2\times3.62$

$width = 7.24\ mm$

Hence, The width of the central bright fringe is 7.24 mm.

5 0

2 years ago

A vertical spring launcher is attached to the top of a block and a ball is placed in the launcher, as shown in the figure. While

kvasek [131]

For a vertical spring launcher is attached to the top of a block and a ball is placed in the launcher, the position of the ball will be behind the box

<h3>What will be the position of the ball relative to the spring launcher?</h3>

Generally, the equation for the conservation of momentum principle is mathematically given as

(M+m) V1 = M*V2

Therefore, with the ball moving forward we have that; the ball at top it wii be behind the box,