All categories

4 years ago

[TRUE/FALSE] If an object is moving at constant velocity it must be in equilibrium.

Physics

1 answer:

DENIUS [597]4 years ago

4 0

Answer:

yes

Explanation:

objects with constant velocity also have zero net external force. this means the forces on the object are balanced. this mean they are in equilibrium

You might be interested in

The table lists the mass and charge of a proton and a neutron.

Olegator [25]

The gravitational force is much larger than the electrical force for any distance between the particles.

Explanation:

The gravitational force between two particles is given by:

$F=\frac{Gm_1 m_2}{r^2}$

where

G is the gravitational constant

m1, m2 are the masses of the two particles

r is the separation between the two particles

The electric force between two particles is given by:

$F=\frac{kq_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1, q2 are the charges of the two particles

r is the separation between the two particles

In this problem, we are comparing the gravitational force and the electric force between a proton and a neutron.

We must immediately notice that the charge of the neutron is zero, since it is electrically neutral:

q = 0

This means that the electric force between the proton and the neutron is always zero, regardless of their distance. And therefore, since their masses is not zero (and the gravitational force is never zero), the correct answer is

The gravitational force is much larger than the electrical force for any distance between the particles.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

About electrical force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

4 0

3 years ago

Read 2 more answers

According to Archimedes' principle, the mass of a floating object equals the mass of the fluid displaced by the object. A 150-lb

Archy [21]

Answer:

Density of the swimmer = $0.0342\ lbm/in^3$ .

Explanation:

Assuming,

$\rho$ = density of the swimmer.

$\rho_w$ = density of the water.

$m$ = mass of the swimmer.

$m_w$ = mass of the water displaced by the swimmer.

$V_w$ = volume of the displaced water.

$V$ = volume of the swimmer.

Given:

$m=150\ lbm.$
$\rho_w = 0.036\ lbm/in^3.$

The density of an object is defined as the mass of the object per unit volume.

Therefore,

$\rho =\dfrac{m}{V}\ \Rightarrow m = \rho V\ \ .........\ (1).$

Since only 95% of the body of the swimmer is inside the water, therefore,

$V_w = 95\%\ \text{of}\ V=\dfrac{95}{100}\times V = 0.95V.$

According to Archimedes' principle,

$m=m_w\\$

Using (1),

$\rho V=\rho_w V_w\\\rho V = 0.036\ lbm/in^3\times 0.95 V\\\rho=0.036\times 0.95\ lbm/in^3=0.0342\ lbm/in^3.$

3 0

4 years ago

The particles ejected from the sun during a coronal mass ejection is called

ipn [44]

Answer:

Plasma

Explanation:

A Coronal Mass Ejection (CME) is an outburst of energy that occurs near the outer part of the sun's atmosphere which causes a production of plasma along with a magnetic field.

The outermost part of the sun's atmosphere is called the Solar Corona Although difficult to see, the corona can be seen during a total solar eclipse.

Plasma from CME are clouds of magnetized electrically charged particles which the solar wind causes to travel at a speed of 1.6 million km/hr.

7 0

3 years ago

A person takes a trip, driving with a constant

podryga [215]

For this problem, we are asked to calculate for the distance traveled. We set up the equations as follows:
Distance = 61 km/hr * (time + 20.8/60 s) Distance = 98.5 km/hr * time

We equate the two equations, then we can solve for the time spent on the trip. Hope this answers the question. Have a nice day.

8 0

3 years ago

A point charge gives rise to an electric field with magnitude 2 N/C at a distance of 4 m. If the distance is increased to 20 m,

worty [1.4K]

Answer:

0.08 N/C

Explanation:

Electric Field: This is defined as the force per unit charge exerted at a point. The expression for electric field is given as,

E = Kq/r².............................. Equation 1

Where E = Electric Field, q = Charge, k = proportionality constant, r = distance.

making q the subject of the equation,

q = Er²/k............................... Equation 2

Given: E = 2 N/C, r = 4 m,

Substitute into equation 2

q = 2(4)²/k

q = 32/k C.

When r is increased to 20 m,

E = k(32/k)/20²

E = 32/400

E = 0.08 N/C.

Hence the electric Field = 0.08 N/C

5 0

4 years ago