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4 years ago

[TRUE/FALSE] If an object is moving at constant velocity it must be in equilibrium.

Physics

1 answer:

DENIUS [597]4 years ago

4 0

Answer:

yes

Explanation:

objects with constant velocity also have zero net external force. this means the forces on the object are balanced. this mean they are in equilibrium

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To leave the gravitational pull of the Earth, and explore other planets, satellites must have at least:

Alexxx [7]

Answer:

To explore the other planets, the satellite must have the velocity more than the escape velocity.

Explanation:

The minimum velocity required by any object to escape from the earth gravitational pull is called the escape velocity.

The escape velocity for any planet depends on the mass of planet and radius of planet. It does not depends on the mass of object. The escape velocity is same for any mass for a particular planet.

So, to explore the other planets, the satellite must have the velocity more than the escape velocity.

7 0

3 years ago

A particle whose speed is 50 m/s moves along the line from A(2,1) to B(9,25). Find its velocity vector in the form of ai +bj.

Kitty [74]

To write it in the form ai + bj, we need to find a and b which are:

a = x component

b = y component

length of x = 9 – 2 = 7

length of y = 25 – 1 = 24

tan θ = 24 / 7

θ = 73.74°

a = (50 m/s) cos 73.74

a = 14 m/s

b = (50 m/s) sin 73.74

b = 48 m/s

Hence,

14i + 48j

3 0

3 years ago

An object moving due to gravity can be described by the motion equation y=y0+v0t−12gt2, where t is time, y is the height at tha

Lynna [10]

Answer: 6.45 s

Explanation:

We have the following equation:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0$ is the height when the rock hits the ground

$y_{o}=75 m$ the height at the edge of the cilff

$V_{o}=20 m/s$ the initial velocity

$g=9.8 m/s^{2}$ acceleration due gravity

$t$ time

$0=75 m+(20 m/s)t-(4.9 m/s^{2})t^{2}$ (2)

Rearranging the equation:

$-(4.9 m/s^{2})t^{2} + (20 m/s)t + 75 m=0$ (3)

At this point we have a quadratic equation of the form $at^{2}+bt+c=0$ , and we have to use the quadratic formula if we want to find $t$ :

$t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ (4)

Where $a=-4.9$ , $b=20$ , $c=75$

Substituting the known values and choosing the positive result of the equation:

$t=\frac{-20\pm\sqrt{20^{2}-4(-4.9)(75)}}{2(-4.9)}$ (5)

$t=6.453 s$ This is the time it takes to the rock to hit the ground

8 0

3 years ago

Forms when heat, pressure, or fluids act on igneous, sedimentary, or other metamorphic rock to change its form or composition, o

BARSIC [14]

I think its a metamorphic rock because i know 100% that a metamophic rocks are created by heat and pressure

4 0

3 years ago

If a car moves with a uniform speed of 2m/s in a circle of radius 0.4m, what is its angular speed?

REY [17]

Answer:

The car's angular speed is $\frac{rad}{s}$ .

Explanation:

Angular velocity is usually measured with $\frac{radians}{sec}$ , so I'm going to use that to answer your question.

The relationship between tangential velocity and angular velocity (ω) is given by:

$V = \omega R$

Using the values from the question, we get:

$2 \frac{m}{s} = \omega (0.4m)$

$\omega = 5 \frac{rad}{s}$

Therefore, the car's angular speed is $5 \frac{rad}{s}$ .

Hope this helped!

3 0

3 years ago