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frutty [35]
4 years ago
13

Protons are released from rest in a Van de Graaff accelerator. They start from a region where the potential is 7.15 MV then trav

el through a vacuum region to a region where the potential is zero. Find the speed of the protons when they reach the zero potential region. (proton mass -1.66 x 1027 kg) A) 1.40 x 10 m/s B) 9.68 x 1014m/s C) 3.70x 10' m/s D) 2.62 x 10 m/s
Physics
1 answer:
Debora [2.8K]4 years ago
6 0

Answer:

3.7 x 10⁷ m/s

Explanation:

ΔV = Potential difference through which the proton moves = 7.15 MV = 7.15 x 10⁶ Volts

q = magnitude of charge on the proton = 1.6 x 10⁻¹⁹ C

v = speed of the proton as it reach zero potential region

m = mass of the proton = 1.66 x 10⁻²⁷ kg

Using conservation of energy

Kinetic energy gained by proton = Electric potential energy lost

(0.5) m v² = q ΔV

(0.5) (1.66 x 10⁻²⁷) v² = (1.6 x 10⁻¹⁹) (7.15 x 10⁶)

v = 3.7 x 10⁷ m/s

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Answer:

1) Chemical to mechanical (calories -> muscle contractions)

2) mechanical to mechanical (muscle -> motion)

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Explanation:

3 0
3 years ago
Explain the increase in pressure of a gas when its volume is decreased at constant<br> temperature.
Dmitriy789 [7]

Answer:

For a gas held at constant temperature, we can apply Boyle's law, which states that the product between the gas pressure and its volume is constant:

PV=const.

where

P is the pressure

V is the volume

As we see from the equation, P and V are inversely proportional to each other: this means that when the volume is decreased, the pressure increases, and vice-versa. The reason for that is that when the volume is decreased, the gas is compressed, so the molecules of the gas come closer to each other, so they collide more frequently with the wall of the container, exerting therefore a greater pressure.

7 0
4 years ago
How much time should be allowed for a 605-mile car trip if the car will the traveling at an average speed of 55 Miles per hour?
Luda [366]
T = d/s

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Hope that helps!!
3 0
3 years ago
Read 2 more answers
with respect to air the refractive index of ice is 1.31 and that of rock salt is 1.54 calculate the refractive index of rock sal
abruzzese [7]

Answer:

1.17

Explanation:

Given that,

The refractive index of ice wrt air = 1.31

The refractive index of rock salt wrt air = 1.54

We need to find the refractive index of rock salt with respect to ice.

We know that,

refractive index = (speed of light in air or vaccum)/( speed of light in that medium)

So,

The speed of light in ice = c/(1.31)

The speed of light in rock salt = c/(1.54)

So, the refractive index of rock salt with respect to ice​ is :

\mu=\dfrac{1.54}{1.31}\\\\=1.17

So, the required refractive index of rock salt wrt ice is 1.17.

4 0
3 years ago
Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. In addi
ra1l [238]
When you put that into a Punnett square you first use the FOIL method because this is a dihybrid case where two traits are considered. This will be the resulting Punnett square:


           PL      Pl        pL       pl

PL    PPLL   PPLl   PpLL   PpLl

Pl     PPLl    PPll     PpLl    Ppll

pL    PpLL    PpLl    ppLL   ppLl

pl     PpLl     Ppll      ppLl    ppll

Now based on the Punnett square above, you can get the ratio. Remember that the dominant trait will always be expressed when you count phenotype combinations so as long as there is a capital letter in the combination, it will always be the one expressed. 

So there are 9 polka dot, long eyelashes(PL), 3 polka dot, short eyelashes (Pl), 3 solid color, long eyelashes (pL), 1 solid short eyelashes(pl).

So your answer is D. 9:3:3:1 ratio
8 0
3 years ago
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