1. If a rock is dropped from a 600 meter cliff, how long will it take to hit the ground? Dl
1 answer:
Answer:
11.1s
Explanation:
Given parameters:
Height of cliff = 600m
Unknown:
How long it takes to hit the ground = ?
Solution:
To solve this problem, we use one of the kinematics equation;
H = ut + gt²
H is the height
u is the initial velocity = 0m/s
t is the time taken
g is the acceleration due to gravity
600 = x 9.8 x t²
600 = 4.9t²
t² = 122.5
t = 11.1s
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Answer: a. m = 7.7 kg
b. V = 435.52 in³
c. m = 1927 kg
d. V = 335.37 cm³
e. m = 3 kg
Explanation: <u>Density</u> is the ratio of mass per volume, i.e., it's the measure of an object's compactness. Its representation is the greek letter ρ.
The formula for density is
Density's unit in SI is kg/m³, but it can assume lots of other units.
Some unit transformations necessary for the resolution of the question:
1 L = 1 dm³ = 1000 cm³
1 in³ = 16.3871 cm³
1 g = 0.001 kg
a. V = 1.34 L = 1340 cm³
m = 5.75 * 1340
m = 7705 g => 7.705 kg
Mass of object 1 with volume 1.34L is 7.7 kg.
b. A cube's volume is calculated as V = side³
V = 7.58³
V = 435.52 in³
Volume of object 2 is 435.52 in³.
c. Using 1 in³ = 16.3871 cm³ to change units:
V = 435.52 * 16.3871
V = 713689.4 cm³
Then, mass will be
m = 2.7 * 713689.4
m = 1926961.4 g => 1927 kg
Mass of object 2 is 1927 kg.
d. Volume of a sphere is calculated as
Diameter is twice the radius, then r = 4.31 cm.
Volume is
V = 335.37 cm³
Volume of object 3 is 335.37 cm³.
e.
m = 8.96 * 335.37
m = 3004.91 g => 3 kg
Mass of object 3 is 3 kg.