Answer:
It has a lower density in its solild stae than it does in its liquid state.
Explanation:
Ice floats, allowing life underneath to leave despite the top freezing.
Answer:
C.)Air is made up of atoms of one elements
<u>Answer:</u>
<em>To raise the pH of the solution to 3.10 we have to add 2.34 L of water.</em>
<u>Explanation:</u>
<em>Given that the pH of the solution of HCl in water is 2.5.</em> Here the solution’s pH is changing from 2.5 to 3.10 which means the acidic nature of the solution is decreasing here on dilution.
ions contribute to a solution’s acidic nature and
contribute to a solution’s basic nature.
The equation connecting the concentration of
and pH of a solution is pH= ![-log[H^+]](https://tex.z-dn.net/?f=-log%5BH%5E%2B%5D)
<em>![[H^+]= 10^(^-^p^H^)](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%2010%5E%28%5E-%5Ep%5EH%5E%29)
</em>
<em>When the pH is
</em>
<em>On dilution the concentration of a solution decreases and volume increases.</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>Volume of water to be added
</em>
<em>
</em>
Answer:
7,94 minutes
Explanation:
If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the r<em>eaction rate does not depend on the concentration of the reactants. </em>
For the zero-order reactions, concentration-time equation can be written as follows:
[A] = - Kt + [Ao]
where:
- [A]: concentration of the reactant A at the <em>t </em>time,
- [A]o: initial concentration of the reactant A,
- K: rate constant,
- t: elapsed time of the reaction
<u>To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.</u>
Data:
K = 4.2 ×10−3atm/s,
[A]o=[HBr]o= 2 atm,
[A]=[HBr]=0 atm (all HBr(g) is gone)
<em>We clear the incognita :</em>
[A] = - Kt + [Ao]............. Kt = [Ao] - [A]
t = ([Ao] - [A])/K
<em>We replace the numerical values:</em>
t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes
So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).