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Darina [25.2K]
2 years ago
12

The second electron shell of an atom can hold a maximum of ______ electron(s).

Chemistry
1 answer:
lawyer [7]2 years ago
5 0
Can hold max of 8 electrons
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If one parent has sickle cell anemia and the other parent is a carrier, what is the possibility that their child will have sickl
earnstyle [38]
It’s a 50 50 chance unless one parent has a dominate gene
5 0
3 years ago
A carbon atom with 6 protons, 6 electrons, and 6 neutrons would have a mass number of
Nata [24]
12, electrons dont have mass. only protons and neutrons do
7 0
3 years ago
An atom that has one or two valence electrons is most likely to be - Nonreactive only
meriva

Answer:

C) Highly reactive

Explanation:

An atom with one or two valence electrons more than a closed shell is highly reactive, because the extra valence electrons are easily removed to form a positive ion

4 0
3 years ago
Determine the heat of reaction (ΔHrxn) for the combustion of ethanol (C2H5OH) by using heat of formation data: C2H5OH (l) + 3 O2
egoroff_w [7]

Answer:

\Delta H_{rxn}=-1234.782kJ

Explanation:

\Delta H_{rxn}=\sum [n_{i}\times \Delta H_{f}^{0}(product)_{i}]-\sum [n_{j}\times \Delta H_{f}^{0}(reactant_{j})]

Where n_{i} and n_{j} are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).

\Delta H_{f}^{0} is standard heat of formation.

So, \Delta H_{rxn}=[2mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[3mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{2}H_{5}OH)_{l}]-[3mol\times \Delta H_{f}^{0}(O_{2})_{g}]

or, \Delta H_{rxn}=[2mol\times -393.509kJ/mol]+[3mol\times -241.818kJ/mol]-[1mol\times -277.69kJ/mol]-[3mol\times 0kJ/mol]

or, \Delta H_{rxn}=-1234.782kJ

4 0
3 years ago
If a sample of CO gas at 1.977 atm has a volume of 517.4 mL and the pressure is changed to
Mekhanik [1.2K]

Answer:

The answer to your question is V2 = 333.9 ml

Explanation:

Data

Pressure 1 = P1 = 1.977 atm

Volume 1 = V1 = 517.4 ml

Pressure 2 = P2 = 3.063 atm

Volume 2 = V2 = ?

Process

To solve this problem use Boyle's law

              P1V1 = P2V2

-Solve for V2

              V2 = P1V1/P2

-Substitution

              V2 = (1.977 x 517.4) / 3.063

-Simplification

              V2 = 1022.9 / 3.063

-Result

              V2 = 333.9 ml

3 0
3 years ago
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