Explanation:
Standardization is the process of creating protocols to guide the creation of a good or service based on the consensus of all the relevant parties in the industry. ... Standardization also helps in ensuring the safety, interoperability, and compatibility of goods produced.
Answer:
The answer is 3
C2H5OH + O2 CO2 +H2O (unbalanced)
C2H5OH +3O2(g). 2CO2(g)+3H2O(balanced)
Answer:
(1). The vapor pressure is 91 mmHg at 20°C.
(2). No, benzene will not boil at sea level.
Explanation:
Benzene, C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mol and Melting point of 5.5 °C. One of the importance or the uses of benzene is in the making of fibres and plastics.
The vapour pressure of benzene can be gotten from the table showing the vapor pressure of different liquids.
Boiling point can simply be defined as the point or the temperature in which the vapor pressure is the same with the atmospheric pressure.
The atmospheric pressure is 760mmHg, while the vapor pressure at sea level is at the temperature of 15°C which is equal to 71 mmHg( from the table showing the vapor pressure of different liquids).
71 mmHg is not equal to 760 mmHg, thus, at sea level Benzene will not boil.
in solid matter, atoms or molecules pack close to each other in fixed locations; in gases, atoms or molecules pack about as closely as they do in solid matter, but they are free to move;
Answer:
Volume of the 
gas at 44°C is <u>258 ml.</u>
Explanation
here,
using Charles' law ,
where , V= initial volume v= final volume
T=initial temperature t = final temperature
Given - pressure is constant ,
so , putting the values -
V= 240ml
T= 22 + 273K = 295K (since converting celsius into kelvin that
is +273K )
v =?
t = 44+ 273K = 317K
Now , putting the given values in charles' law ,
240ml x317K = v x 295K (through cross multiplication )
v =
= 258ml .
thus ,<u> the volume of carbon dioxide in a container at 44°C IS 258ml .</u>
