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Effectus [21]
3 years ago
5

In the Bohr model of the atom, an electron in an orbit has a fixed energy level and to move between orbitals what needs to absor

bed or released?
quantum of energy
light
heat
electricity
Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
3 0
The answer is heat hope i helped

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What is the advantage of rusting​
Naddika [18.5K]

Answer:

Provide more strength

Explanation:

Rust is metal that has been oxidised . Oxides are usually more fragile and porous than their crystals metal equivalents. Some oxides, such as Aluminum oxide, are useful because they have a thin, strong shell that protects the metal from further corrosion.

8 0
3 years ago
18. What is the percent by mass sugar of a solution made by dissolving 12.45 grams of sugar in 100 grams of water?
Fantom [35]

The percent by mass sugar of a solution : 11.07%

<h3>Further explanation</h3>

Given

mass of sugar = 12.45 g

mass of water = 100 g

Required

The percent by mass

Solution

Mass of solution :

\tt mass~sugar+mass~water=12.45+100=112.45~g

Percent mass of sugar :

\tt \%mass=\dfrac{mass~sugar}{mass~solution}\times 100\%\\\\\%mass=\dfrac{12.45}{112.45}\times 100\%=11.07\%

6 0
3 years ago
Acids or bases can be tested by chemical_________
DedPeter [7]

Answer:

acids or bases can be tested

by chemical indicators

7 0
2 years ago
Read 2 more answers
From the given elements Na, P , Ca ,Br which one has highest first ionization energy , ,smallest atomic size , most metallic cha
madam [21]

Answer:

highest first ionization energy - Br

smallest atomic size - Br

most metallic character - Na

Explanation:

Ionization energy of Br is higher than P because higher zeff value

Sodium is more metallic than calcium because it is able to loose electron more readily as compared to calcium because of higher electro positivity.

Atomic radius of Br is the smallest as its atomic radius is 114, P (115), Ca (197), Na (186)

 

 

5 0
3 years ago
What is the electric field (in N/C) at a point 5.0 cm from the negative charge and along the line between the two charges?
Natali [406]

Answer: E = 2.455 x 10^5 N/C

Explanation:

q1 = 1.2x10^-7C

q2 = 6.2x10^-8C

Electric field, E = kQ/r²

where k = 9.0x10^9

since the location is (27 - 5)cm from q1

hence electric field, E1 = k*q1/r²

E1= (9x10^9 x 1.2x10^-7)/(0.22)² = 22314.05 N/C

for q2:

E1 = k*q2/r²

E2 at 5cm

E2 = (9x10^9 x 6.2x10^-8)/(0.05)² = 223200 N/C

Hence, the total electric field at 5cm position is

E = E1 + E2

E = 22314.05 + 223200 = 245514.05 N/C

E = 2.455 x 10^5 N/C

4 0
3 years ago
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