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Brilliant_brown [7]
3 years ago
14

What reaction is a match burning

Chemistry
2 answers:
Kamila [148]3 years ago
7 0

A familiar example is a lighted match. When a match is struck, friction heats the head to a temperature at which the chemicals react and generate more heat than can escape into the air, and they burn with a flame.

vlabodo [156]3 years ago
5 0
<h2>Answer with Explanation </h2>

The match stick consists of chemicals like potassium, phosphorous, chlorine and lead. The burning of match stick is a chemical reaction called as combustion in this process the red phosphorus converted into white phosphorus to blow the match stick. Initially, the heat is generated by pushing the matching stitch on a specific surface and by the chemical reaction makes the match stick burns. Ultimately, the chemical burns then the wood burns on which the chemical is stuck.


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Silicon carbide, SiC, is commonly known as carborundum. This hard substance, which is used commercially as an abrasive, is made
mrs_skeptik [129]

Mass of SiC = 2 g

<h3>Further explanation</h3>

Given

Reaction

SiO₂(s) + 3C(s) → SiC(s) + 2CO(g)

3.00 g of SiO₂

4.50 g of C

Required

mass of SiC

Solution

mol SiO₂ (MW=60,08 g/mol) :

= 3 g : 60.08 g/mol

= 0.0499

mol C(Ar = 12 g/mol) :

= 4.5 g : 12 g/mol

= 0.375

mol : coefficient of reactants =

SiO₂ : 0.0499/1 = 0.0499

C : 0.375/3 = 0.125

SiO₂ as a limiting reactant(smaller ratio)

Mol SiC based on mol SiO₂ = 0.0499

Mass SiC :

= mol x MW

= 0.0499 x 40,11 g/mol

= 2 g

3 0
2 years ago
If you are given 1.709 moles of solute, and you dilute it to make 2.10 liters of solution, what is the resulting molarity (M)? (
azamat
Moles/MxL 

1.709moles/2.10L =<span>0.814M</span>
4 0
3 years ago
A sample of hydrated magnesium sulfate (MgSO4)
yaroslaw [1]

Answer:

MgSO4.7H2O

Explanation:

Let the formula for the hydrated magnesium sulphate be MgSO4.xH2O

Mass of the hydrated salt (MgSO4.xH2O) = 12.845g

Mass of anhydrous salt (MgSO4) = 6.273g

Mass of water molecule(xH2O) = Mass of the hydrated salt — Mass of anhydrous salt = 12.845 — 6.273 = 6.572g

Now,we can obtain the number of mole of water molecule present in the hydrated salt as follows:

Molar Mass of hydrated salt (MgSO4.xH2O) = 24 + 32 + (16x4) + x(2 + 16) = 24 + 32 + 64 + x(18) = 120 + 18x

Mass of xH2O/ Molar Mass of MgSO4.xH2O = Mass of water / mass of hydrated salt

18x/120 + 18x = 6.572/12.845

Cross multiply to express in linear form

18x x 12.845 = 6.572(120 + 18x)

231.21x = 788.64 + 118.296x

Collect like terms

231.21x — 118.296x = 788.64

112.914x = 788.64

Divide both side by 112.914

x = 788.64 /112.914

x = 7

Therefore the formula for the hydrated salt (MgSO4.xH2O) is MgSO4.7H2O

6 0
2 years ago
What did Rutherford's gold foil experiment tell about the atom?​
VLD [36.1K]

The alpha particles that were fired at the gold foil were positively charged. ... These experiments led Rutherford to describe the atom as containing mostly empty space, with a very small, dense, positively charged nucleus at the center, which contained most of the mass of the atom, with the electrons orbiting the nucleus.

hope this helped

3 0
2 years ago
When an electron in an atom spontaneously jumps from a higher energy state to a lower energy state, the atom?
vlabodo [156]
If an atom suffers from a collision, that causes an electron to jump from a lower to higher state, it is called collisional excitation 
6 0
2 years ago
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